Can somebody help me?

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November 9th, 2012, 08:55 PM

WandyLau

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Join Date: Oct 2011

Posts: 29

Time spent in forums: 5 h 39 m 44 sec
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Can somebody help me?

I wrote some lines to extract the duplicated data from a piece of sorted data about 496 ,whose is formatted as "12 23 34 45 1234". I　just want to get the ones who have the same last for numbers.And I have already known that there are 48 couples in all .So I wrote a piece of script but I only got a half ,just 24 couples.I checked that it just skipped some data.I can't understand it. Perhaps some bugs exist in my lines ,but I can not figure it out .Some body helps me please. Thank a lot in advance!! Code as follows>>

Code:

#!/usr/lib/env python

f = open("bit16_21",'r')
lines = f.readlines()
f.close()
fobj = open('dup','w')
i = 0

while i<496:
    line = lines[i]
    j = i+1
    if  j<496 and line[9:] == lines[j][9:]:
        fobj.write(line)
        fobj.write(lines[j])
    i += 1
        
        
fobj.close()
print 'done!'

And I wonder if I do not know that it has 48 couples. Some one piece maybe have 3 or more duplicated ones how to get all the duplicated ones.I just trapped by this .

November 9th, 2012, 10:27 PM

WandyLau

Registered User

Join Date: Oct 2011

Posts: 29

Time spent in forums: 5 h 39 m 44 sec
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Quote:

Originally Posted by WandyLau

Code:

#!/usr/lib/env python

f = open("bit16_21",'r')
lines = f.readlines()
f.close()
fobj = open('dup','w')
i = 0

while i<496:
    line = lines[i]
    j = i+1
    if  j<496 and line[9:] == lines[j][9:]:
        fobj.write(line)
        fobj.write(lines[j])
    i += 1
        
        
fobj.close()
print 'done!'

And I wonder if I do not know that it has 48 couples. Some one piece maybe have 3 or more duplicated ones how to get all the duplicated ones.I just trapped by this .

Yeah,I got the silly bug ,I counted the wrong number which should be like :line[11:] == lines[j][11:] . OMG，It nearly drived me out of my mind ,this little bug . Small mind-absence results in big mistake.
Now I wonder if there are more than two duplicated ones.How to handle it.....

November 9th, 2012, 11:36 PM

WandyLau

Registered User

Join Date: Oct 2011

Posts: 29

Time spent in forums: 5 h 39 m 44 sec
Reputation Power: 0

Solved

Quote:

Originally Posted by WandyLau

Wow,I finally made it. Just some tricks. Ok I'will post the script,not so hard. But I am a green hand in programming so not easy for me!! Happy..

Code:

#!/usr/lib/env python

f = open("bit16_21",'r')
lines = f.readlines()
f.close()
fobj = open('dup','w')
i=0
while i in range(496):
    line = lines[i]
    j = i+1
    n = j+1
    if j<496 and line[11:] == lines[j][11:]:
        fobj.write(line)
        fobj.write(lines[j])
        while  n<496:
            if lines[j][11:] == lines[n][11:]:
                fobj.write(lines[n])
                n += 1
                
                
            else:
                i = n
                break
    else:
        i = j

fobj.close()
print 'done!'

November 10th, 2012, 07:19 AM

KING-OLE

Registered User

Join Date: Nov 2012

Location: Texas

Posts: 24

Time spent in forums: 5 h 54 m 45 sec
Reputation Power: 0

Good job.

You may consider using .split to create a list containing each of the values in the line you read from the file.

Here's an example with 2 strings that I convert to 2 lists, and compare the last element:

Code:

s1="41 42 14 15 2012"
s2="44 63 44 78 2012"

l1=s1.split()
l2=s2.split()

if l1[4]==l2[4]:
  print("They match")

This way, your program would work if the first 4 values did not have the same digits.

Example: This would work with the split solution, but not with your solution:

Code:

s1="41 2 14 15 2012"
s2="44 63 144 78 2012"

l1=s1.split()
l2=s2.split()

if l1[4]==l2[4]:
  print("They match")

Can somebody help me?

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