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#1
March 13th, 2004, 12:14 AM
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comparing user input against a string (newbie)
Hi, i'm trying to break out of a loop whenever user type in "q".
However if ui=="q": never return true when i type in "q"!?!? what is the reason? while: print "Pls input the nominated text: " ui = str(sys.stdin.readline()) if ui=="q": break
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#2
March 13th, 2004, 02:29 AM
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Re: comparing user input against a string (newbie)
I believe the problem is that sys.stdin.readline() will read in the whole line, including the carriage return ("\n") at the end. According to the Python docs:
Quote:
If you wish to remove the newline character try rstrip(). Here's your code modified to (hopefully) work: Code:
while 1:
print "Pls input the nominated text: "
ui = sys.stdin.readline()
ui = ui.rstrip("\n")
if ui=="q":
break
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#4
March 13th, 2004, 09:03 AM
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A few similar examples of how to do this the easy way.
Code:
#!/usr/bin/env python
user = ''
while user != 'quit':
user = raw_input('Pls input the nominated text: ')
or Code:
#!/usr/bin/env python
user = raw_input('Pls input the nominated text: ')
while user != 'quit':
user = raw_input('Pls input the nominated text: ')
Of course this exits if the user enters 'quit' but not hard to change to 'q'. Mark.
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#5
March 13th, 2004, 02:24 PM
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You should transform the text to be all upper-case letters or all lower-case letters. Then make the quit command 'q' and 'quit'.
So if a user puts in QuIt, it will be transformed into 'quit'.
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