counter does not go forward

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July 23rd, 2003, 12:35 PM

tricia

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counter does not go forward

Hi!

I cannot understand why the counter in the following does not work. Any ideas? Thanks in advance.

temp = a list of different cases,
eg: temp = [['texta', '234', '345'],['textb', '3453', '43']]

result = the list of numbers found in temp
eg: result = [234, 345, 3453, 43]

Code:

for i in result: 
     d = d + 1 
     sum = result[d]
     output.write(str(result[d]) + ' ')
     s = d
     while s != len(result):
       s = s + len(result)/len(temp)
       sum = sum + result[s]
       output.write(str(result[s]) + ' ')
       output.write(str(sum) + NL)

(my apologies, I don't know why the indentation is messed up)

Last edited by tricia : July 23rd, 2003 at 06:32 PM.

July 23rd, 2003, 12:44 PM

percivall

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Use the '#' button to insert code.

July 23rd, 2003, 12:54 PM

SolarBear

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The way I see it, you did not give any initial value to d. So Python is saying "Yeah, I'm adding 1 to WHAT ?". Python does not even know what type d is if you don't initialize it. Simply add d = 0 at the beginning of your code.

July 23rd, 2003, 12:58 PM

tricia

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my mistake, i forgot to add it. I do have d=0 just before 'for i in result:' but it still won't do it. d just gets stuck to 0.

July 23rd, 2003, 12:59 PM

tricia

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it gets stuck to 1 i meant.

July 23rd, 2003, 01:08 PM

netytan

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Is this a counter script for a web page, as in CGI? Whats it surposed to do? Also this can't be the whole script, can you post the rest please?

Take care,
Mark.

July 23rd, 2003, 06:21 PM

SolarBear

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This may not be your problem, but why don't you use

Code:

for d in result

? You're creating a counter variable (i) but you're not using it.

And as netytan said, post the whole code.

July 23rd, 2003, 09:21 PM

CottonBuds

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Hi tricia,

It seems that you're having a bit of confusion in 'nested' loops (probably)

I presume python nested loops works as any other programming language. eg: first the outer loop executed once, then executes the inner until it finishes or finds a condition, the again the outer loop again.... isn't it right?

As I can see from your code you've got a 'for' loop which you you want the var 'd' to increment.

Then you're using a 'while' loop.
and you've alredy told us that 'd' is being initialise somewhere in your code. OK...
let's see now, I think there's something wrong in the while 'loop' condition....

This is what your loop code does:
1. Goes to 'for' then blah blah
2. Goes in the 'while s != len(result):'
presumably: s = d which is 1 and len(result) = 4 or 5 or 6.
Which in this case you need it to be 1 != 4, and the condition is correct!
Then s = s + len(result)/len(temp)
s = 1 + 4/2 equals 3 then while loop check condition 3 != 4 - nop
s = 3 + 4/2 equals 5 then while loop check condition 5 != 4 - nop
s = 5 + 4/2 equals 7 then while loop check condition 7 != 4 - nop
... and this goes forever ....

When you get in 'while' loop the program stay in it, like forever....
how do you get out of there?

Code:

     while s != len(result):
       s = s + len(result)/len(temp)
       sum = sum + result[s]
       output.write(str(result[s]) + ' ')
       output.write(str(sum) + NL)

A solution:
If you can find a way to get out from the while loop. 'd' might be able to increment.

I don't know if I'm right, anyway good luck.

Mina Saiiiii!

Last edited by CottonBuds : July 23rd, 2003 at 09:34 PM.

July 24th, 2003, 08:03 AM

tricia

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here is the full code, hope it helps.

Code:

text = [['txt1-0', '123', '231241', '23'],['txt1-1', '1233','23','413'],['txt2-0','34','3','5']]

def add(text):
  temp = []
  ## read the file name, if the next filename has the same main digit, continue till you find sth different
  ## if not, go back and add the numbers as if in columns, and create a new entry.
  ## eg. text = [['txt1', '1356', '231264', '436],['txt2','34','3','5']]
  a = -1; first = a + 1
  for i in text:
    a = a + 1
    try:
      if text[a+1][0][3] == text[first][0][3]:
        temp.append(i)
      else:
        b = -1; result = []
        for i in temp: ## gather all the scores in one list
          b = b + 1; c = -1
          for s in i[1:]:
            c = c + 1
            result = result + [float(temp[b][1:][c])]
            d = -1; sum = 0
            for i in result: 
              d = d + 1 
              sum = result[d]
              s = d
              while s != len(result):
                s = s + len(result)/len(temp)
                sum = sum + result[s]
    except IndexError: pass

there should be more but i haven't written it yet.

Last edited by tricia : July 24th, 2003 at 08:08 AM.

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