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  #1  
Old January 25th, 2013, 08:55 AM
trukodo trukodo is offline
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File organisation

hi im trying to create a script that would allow for me to be able to have files automatically sorted in a folder.
there are a few things which i need to be carried out but there is one bit that i cant figure out, what i need to do is be able to get the first character of every file, i then need to create a folder for every unique value the closest i have come to so far is this:
import os
from os import listdir
import dircache
import sys
import shutil
import dircache
import glob

path = "C:\\Users\\hra\\Desktop\\fg"
dirList=os.listdir(path)
for fname in dirList:
print fname

myList = fname
[x[0] for x in myList]
print "my list = ", myList

fCounter = len(glob.glob1("C:\\Users\\hra\\Desktop\\fg","f*"))
mCounter = len(glob.glob1("C:\\Users\\hra\\Desktop\\fg","m*"))
bCounter = len(glob.glob1("C:\\Users\\hra\\Desktop\\fg","b*"))
#print "all files = ", countall
print "f = ", fCounter
print "m = ", mCounter
print "b = ", bCounter

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Old January 25th, 2013, 10:44 AM
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b49P23TIvg b49P23TIvg is offline
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Your description sounds a lot like
Code:
import os

path = "C:\\Users\\hra\\Desktop\\fg"
dirList=os.listdir(path)

# why sort???

first_characters_of_items_in_dirList = [name[0] for name in dirList]
uniques = set(first_characters_of_items_in_dirList)
for d in uniques:
    if (not os.path.isfile(d)) and (not os.path.isfile(d)):
        os.mkdir(d)
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