Help!?

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December 7th, 2012, 11:28 AM

mikejcbs

Registered User

Join Date: Dec 2012

Posts: 3

Time spent in forums: 37 m 48 sec
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Help!?

I am trying to write a program that finds any multiples of four between 0-100.
I have gotten this,

x = 0
while x < 100:
x += 1
if x % 4 == 0:
print, (x) ("is a multiple of 4")

But, when it tries to print it give me the error,

Traceback (most recent call last):
File "C:\Users\Jacobs\Desktop\Python\Multiples.py", line 6, in <module>
print, (x) ("is a multiple of 4")
TypeError: 'int' object is not callable
>>>

Any suggestions would be greatly appreciated,

Michael

December 7th, 2012, 12:13 PM

b49P23TIvg

Contributing User

Join Date: Aug 2011

Posts: 3,376

Time spent in forums: 1 Month 2 Weeks 3 Days 12 h 21 m 42 sec
Reputation Power: 383

I suggest that in python
object(parens)
indicates to call a function.

The expression (x) results in an integer, and that's why you got the message. Integers aren't callable.

Integers are objects with methods, as you can see from

Code:

>>> 8     .    __add__(22)
30

Integers don't have a __call__ method.

People usually express addition with + operator. The __add__ method takes place in the darkness behind the curtain.

Code:

for x in range(100):
    if x % 4 == 0:
        print(x , "is a multiple of 4") # looks better in python3

__________________
[code]Code tags[/code] are essential for python code!

December 7th, 2012, 12:16 PM

mikejcbs

Registered User

Join Date: Dec 2012

Posts: 3

Time spent in forums: 37 m 48 sec
Reputation Power: 0

Quote:

Originally Posted by b49P23TIvg

Code:

>>> 8     .    __add__(22)
30

Integers don't have a __call__ method.

People usually express addition with + operator. The __add__ method takes place in the darkness behind the curtain.

Code:

for x in range(100):
    if x % 4 == 0:
        print(x , "is a multiple of 4") # looks better in python3

Thank you so much for your help! I really appreciate it.

December 7th, 2012, 12:26 PM

mikejcbs

Registered User

Join Date: Dec 2012

Posts: 3

Time spent in forums: 37 m 48 sec
Reputation Power: 0

Second question even if I set x to start at 1 it still includes 0 as a multiple any way to prevent this?

December 7th, 2012, 12:33 PM

b49P23TIvg

Contributing User

Join Date: Aug 2011

Posts: 3,376

Time spent in forums: 1 Month 2 Weeks 3 Days 12 h 21 m 42 sec
Reputation Power: 383

Oh, you incremented before you tested. Sure, there are ways around that. Self-help in python is fairly easy.

>>> help(range)

thus

for x in range(1,101):

Your while loop was fine. I chose to expand the knowledge base. I've done it again! String formatting.

Code:

x = 0
while x < 100:
    x += 1
    if x % 4 == 0:
        print('%d is a multiple of 4'%x)

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