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#1
November 20th, 2003, 01:52 PM
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How to zip a file?
Hello All!
I had this idea about a script that would come in handy for me and maybe for somebody else. At this stage I am still learning and this will be beyond my knowledge. If somebody can help me out by showing how to do this? What i want is to search for all files in all directories and if found a file ending in txt extention RAR(winrar) this file and then delete the original file. Thanks Random
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#2
November 20th, 2003, 02:06 PM
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You can use os.path.walk() to walk through a directory tree, and os.path.splitext() to get the extension. See the docs for the os.path module here: http://web.pydoc.org/2.1/posixpath.html
To zip the file up, you'll probably need the zipfile module: http://web.pydoc.org/2.2/zipfile.html Finally, to remove the old file, use os.unlink(): http://web.pydoc.org/2.1/os.html
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#3
November 20th, 2003, 04:01 PM
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Thanks Scorpions4ever!
I have started doing what you sudgested up until the actual process of ziping the the file which did not work. Any advice? Code:
import os.path, zipfile
def action(arg, dirname, file_list):
for file in file_list:
split = os.path.splitext(file)
if (split)[1] == '.txt':
z = zipfile.ZipFile(split[0]+ '.zip', "w")
z.close()
root = 'D:/new folder'
arg = None
os.path.walk(root, action, arg)
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#4
November 20th, 2003, 07:19 PM
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You might find os.walk() easier to work with than os.path.walk() as well as being faster
 , also you can check the file extension for the filenames much easier using the str.endswith method i.e.Code:
if file.endswith('.txt'):
...
do whatever with the file
...
Mark.
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#5
November 20th, 2003, 09:32 PM
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arg you read my mind!! Mr you told me that built in func good you told him as well :P
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