In TkInter: Changing background color, then changing it again after a delay

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November 13th, 2012, 09:13 PM

mikerpiker

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Join Date: Nov 2012

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In TkInter: Changing background color, then changing it again after a delay

I'm trying to make a program that

(1) displays a window with a button in it
(2) when you press the button, the background of the window changes from one color to another...
(3) ...and then changes back to its original color after a short delay (without pressing the button again).

So far, I've managed (1) and (2), but I can't figure out how to implement (3). Here is my code:

Code:

from Tkinter import *  

root = Tk()  

def bthing():    root.configure(background="red")  
b = Button(text="OK", command=bthing) 
b.pack()  

root.configure(background="grey") 
root.geometry("400x400") 
root.mainloop()

I can cause a delay before the background color changes by changing "def bthing(): root.configure(background="red")" to "def bthing(): root.after(1000, root.configure(background="red"))"

But what I want is something like... "root.configure(background="red") THEN root.after(1000, root.configure(background="grey"))"

Can someone point me in the right direction? I have no experience in programming.

November 14th, 2012, 08:55 AM

b49P23TIvg

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Join Date: Aug 2011

Posts: 3,348

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Code:

try:
    import tkinter
except:
    import Tkinter as tkinter

root = tkinter.Tk()

def grey(*args,**kwargs):
    root.configure(background="grey")

def bthing():
    root.configure(background="red")
    root.after(1000, grey)

tkinter.Button(text="OK", command=bthing).pack()

root.configure(background="grey")
root.geometry("400x400")

root.mainloop()

How does this differ from your effort?
root.after(1000, root.configure(background="grey"))
function(arguments) causes python to evaluate the function immediately. I passed the name of a function, just as you did when you wrote command=bthing .

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