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November 17th, 2003, 03:30 AM

xlordt

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IndexError:

Ok i created an irc bot using the socket module, but.. its bugged.. when i am in irc.. and i kill the bot, in my konsole i get this error

Traceback (most recent call last):
File "./4.py", line 39, in ?
print Recv(s,1025)
File "./4.py", line 16, in Recv
if receive[1] == "PRIVMSG" and receive[2] == "Pythonbot":
IndexError: list index out of range

Can anyone tell me what this means?
all so when the bot enters the chan i made it say hello, but when i view my konsole i dont see anything about the bot saing hello all i see is what the users in the irc inputed.. here is the code

Code:

#!/usr/bin/env python

from socket import *
from string import *


def Send(self,data):
 self.send(data)
 
def Recv(self,integras):
 data = self.recv(integras) 
 receive = split(data," ")
 
 if receive[0] == "PING": Send(self,"PONG :"+receive[0]+"\n\r")
 
 if receive[1] == "PRIVMSG" and receive[2] == "Pythonbot": 
  user = split(receive[0],"!") 
  Send(self,"PRIVMSG #bot :Dont bother me im just a stupid bot\n\r")
  return "PRV From"+user[0]+"\\"+receive[3]
  
 #if receive[3] == "!quit": Send(s,"QUIT\n\r")
 
 else: 
  return data
 
s = socket(AF_INET,SOCK_STREAM) #Initializing TCP
msg = 0

try:
 if s.connect(("irc.server.net",6667)) != -1:
 
  Send(s,"NICK Pythonbot\n\r")
  Send(s,"USER localhost localhost localhost : ****YOU\n\r")
  Send(s,"JOIN #bot\n\r")
  msg = "hello"
  Send(s,"PRIVMSG #bot :"+msg+"\n\r")
  
  while 1: 
   print Recv(s,1025)
   msg =+ 1
    
except error, detail:
 print detail[0]

sorry still new to python, and still learning

any suggestions, Since python are not to big on tutorials

Last edited by xlordt : November 17th, 2003 at 03:33 AM.

November 17th, 2003, 09:02 AM

SolarBear

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I guess this could be your mistake :

Code:

Send(s,"NICK Pythonbot\n\r")

You're sending a string to your script with one whitespace.

Code:

receive = split(data," ")

This creates a tuple with 2 elements. So here comes the problem:

Code:

if receive[1] == "PRIVMSG" and receive[2] == "Pythonbot":

I'd say that's the problem. You're trying to access the third element of your 2-tuple ! Remember, Python's lists and tuples work like C arrays : the nth element is accessed by number n-1. So you only need to change it that way :

Code:

if receive[0] == "PRIVMSG" and receive[1] == "Pythonbot":

This should do the trick.

November 17th, 2003, 09:32 AM

netytan

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Wow, very surprised! i figured that an IRC bot would be allot bigger than this, my bad

Anyway looks like you beat me too it solar

.. anyway i think your right, obviously your trying to access values which dont exist X

, too be safe you could check its size before you carry on although you dont 'need' too..

Code:

if len(recieve) > 1:
    ...
    carry on
    ...

, you really don't need the string module anymore (at least in my oppinion), you can do everything the string module does more efficently using string methods i.e.

Code:

receive = data.split()

If you insist on using the string module though you should know that split() defaults to spaces so you should write..

Code:

receive = split(data)

..instead of..

Code:

receive = split(data," ")

Quote:

Solar
This creates a tuple with 2 elements. So here comes the problem:

Its actually a list not a tuple. it may not seem like a big deal but there are allot of things you just can't do with tuples so i figured i'd just point this one out

Mark.

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Last edited by netytan : November 17th, 2003 at 09:35 AM.

November 17th, 2003, 10:27 AM

netytan

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Quote:

def Send(self, data):
...
...

def Recv(self, integras):
...
...

I just knowticed the 'self' option in your function definitions.. really not the best idea X

its would probably help to think of 'self' as a reserved word (although it isnt actually) for use inside classes.. possibly use 'this' or 'object' etc.

Mark.

November 17th, 2003, 04:16 PM

xlordt

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Quote:

This creates a tuple with 2 elements. So here comes the problem:

code:if receive[1] == "PRIVMSG" and receive[2] == "Pythonbot":

are you sure.. cause.. see what im doing is im splitting the data that i get before it enters the irc chan, there for when i split it then receive[1] will be == to PRIVMSG, now receive[0] will be the users host... im confused now

November 17th, 2003, 07:07 PM

netytan

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Ok for everyone else not part of the Netytan -> X meeting, we've solved the problem and X came up with an even smaller piece of code than the one he had before (this one works)

Anyway i created a class to handle this (attached), feel free to download and learn..

Mark.

Attached Files

pyrc.py (921 Bytes, 124 views)

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