[harry3490]

if list1={[x,1,3,4],[y,5,6,7],[x,2,3,4],[z,1,2,3],[y,6,7,8],[hello,3,4,5],[hello,66,99,11]}

I want to print like
For x: values are 1,3,4,2,3,4
For y: values are 5,6,7,6,7,8
For z: values are 1,2,3
For Hello: values are 3,4,5,66,99,11

[SuperOscar]

Originally Posted by harry3490

if list1={[x,1,3,4],[y,5,6,7],[x,2,3,4],[z,1,2,3],[y,6,7,8],[hello,3,4,5],[hello,66,99,11]}

I want to print like
For x: values are 1,3,4,2,3,4
For y: values are 5,6,7,6,7,8
For z: values are 1,2,3
For Hello: values are 3,4,5,66,99,11

You cannot mean quite this. Lists are unhashable, so you cannot create sets whose elements were lists. Also, you possibly meant x, y and hello to be strings, not variables.

If so, you might do:

d = {}
for sublist in list1:
    car, *cdr = sublist
    if car in d:
        d[car].extend(cdr)
    else:
        d[car] = cdr[:]

and print “d”.

[harry3490]

First of all, here x,y,z,hello are string not a variable. And list is defined as like list1={tuple1,tuple2,.........}
tuple1=(x,2,5,6}..

[SuperOscar]

Originally Posted by harry3490

First of all, here x,y,z,hello are string not a variable.

In which case, you should have them surrounded by quotes.

And list is defined as like list1={tuple1,tuple2,.........}
tuple1=(x,2,5,6}..

Again, you use {...} as if you were defining a set instead of a list. Tuples are hashable and can be used in a set, but in your original code you had [...] instead of (...), i.e., lists instead of tuples.

But since both my guesses were correct, the code I provided should work, right?

[Joseph8th]

Yep my first thought was parse list1 into a dictionary of lists, too.

[harry3490]

yeah it is working !! thanks oscar