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#1
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Look Over my Code
Here are a few things that I need to have looked over. I'm pretty sure that they're close to working only they may have 1 or 2 things wrong with them.
Original Code: Code:
Public Function StrToHex(ByVal String1 As String) As String
On Error GoTo EndStr
Dim strTemp As String, strReturn As String, i As Long
For i = 1 To Len(String1)
strTemp = Hex(Asc(Mid(String1, i, 1)))
If Len(strTemp) = 1 Then strTemp = "0" & strTemp
strReturn = strReturn & " " & strTemp
Next i
StrToHex = strReturn
EndStr:
Exit Function
End Function
My code: Code:
def StrToHex():
while i == 1:len(string1)
strTemp = hex(ord(string1[i:1]))
if len(strTemp) == 1:
strTemp = "0"+strTemp
strReturn = strReturn+" "+strTemp
Original Code: Code:
Public Function KillNull(ByVal Text As String) As String
Dim i As Integer
i = InStr(1, Text, Chr(0))
If i = 0 Then
KillNull = Text
Exit Function
End If
KillNull = Left(Text, i - 1)
End Function
My code: Code:
def KillNull(): # Pending approval
KillNull = KillNull()
i = chr(0) in text
if i == 0:
killnull = text
pass
killnull = text[i:1]
Original code: Code:
Public Sub NullTruncString(ByRef Text As String)
Dim i As Integer
i = InStr(Text, Chr(0))
If i = 0 Then Exit Sub
Text = Left(Text, i - 1)
End Sub
My code: Code:
def NullTruncString(): # Pending approval
i = chr(0) in text
if i == 0:
pass
text = text[i:1]
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#2
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One of the advantages of an interpreted language, especially one which has an interactive listener prompt, is that it is much easier to test an individual function or group of functions in isolation; you don't need to set up a whole test harness for it, you just load a copy of the function into the workspace and then write a few tests cases to see if it behave the way you expect it to.
That is to say, you'd have had faster results, with less sarcasm, if you'd just run the damn functions and saw that they do not, in fact, work. just to take the first one, well, right of the bat I could see that the were some syntax errors, so it was clear you hadn't try testing them yourself. Also, the translation of the VB code was incorrect; you dropped the function argument and the return value, you wrote the while loop incorrectly (BTW, it would be easier to use for i in range(len(string1)):, it think) and made a hash of the indentation. Anyway, I fired up DrPython (which I definitely recommend, though I hear Boa Constructor is even better), pasted your code into the editor window, fixed errors I saw, and worked up a simple test. Fixing the obvious problems sbrought out a less obvious one, that the range string1[i:1] should be string1[i:i + 1]; otherwise, it becomes an invalid range once i is greater than zero. Code:
def StrToHex(string1):
strReturn = ""
for i in range(len(string1)):
strTemp = hex(ord(string1[i:i + 1]))
if len(strTemp) == 1:
strTemp = "0" + strTemp
strReturn = strReturn +" "+strTemp
return strReturn
print "'Hello' becomes " + StrToHex("Hello")
(The last line is the test case, which will run automatically when the script is run in the interpreter). Fixing that got the function to the point where the interpreter wouldn't spit it out; however, the test showed that the function was returning a blank string. As a quick sanity check, I dropped into the interactive window, and ran Code:
print(hex(ord('h')))
At this point I decided to leave off, as it was clear - as I had said to you already - that Python's idioms, conventions and libraries were too different from VB's to make a direct translation practical. The two hex() functions have the same purpose, but they are not interchangible. If you want to create a function closer to the one in VB, you might want to see how the Python entries for this 'hex dump chrestomathy' did it. HTH. |
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#3
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Looks like I didn't get round to posting my reply before Firefox crashed..
![]() *sigh* Let me try again quickly... Code:
1 def KillNull(): # Pending approval 2 KillNull = KillNull() 3 i = chr(0) in text 4 if i == 0: 5 killnull = text 6 pass 7 killnull = text[i:1] Line 1: no parameters, so where is the "text" coming from? Line 2: Calling itself? That will just loop then crash! Line 3: i is commonly a counter variable, so that's a bit confusing, but it will work Line 4: The result of "x in y" is True or False, so test i == False isntead for clarity. Line 5: right Line 6: This does nothing. Pass is just a placeholder Line 7: This ignores all text before the null, is that right? Line 8: No return command. Now data can't get into the function, or out, so it's a touch pointless. ----- Same points here for the last bit... Code:
1 def NullTruncString(): # Pending approval 2 i = chr(0) in text 3 if i == 0: 4 pass 5 text = text[i:1] Line 1: Also no parameters Line 2: Same about the True False thing Line 3: This test does nothing. Pass doesn't exit the function, it just does ... nothing. Line 5: Doesn't this do the same as KillNull? Line 6: Also no return command... Depending on what the code actually needs to do, you could probably replace it all with one of the following: Either... Remove a null at the start of a string: Code:
def killNullAtOneEnd(text):
if text.startswith(chr(0)):
return text[1:]
else:
return text
(or use .endswith() and text[:-1] for the end of the string) Or... Dump both the functions completely and remove any null in the string: Code:
text = text.replace(chr(0), "") Or ... Use string.split to get the text either side of the null: Code:
beforeNull, afterNull = text.split(chr(0)) ![]() Last edited by sfb : December 12th, 2004 at 02:54 PM. |
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#4
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Ok, thanks for the help the both of you, I understand this much better now.
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