Need help with this problem. ( Python 3.2.1.1)

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February 15th, 2013, 02:48 PM

Jokus

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Need help with this problem. ( Python 3.2.1.1)

So I have this project for school. We are supposed to make :

h t t p : / / ed.edim.co/9437390/draw_with_loops.txt?Expires=1360962848&Signature=RYlWmjPnkWZTe9Seo7gesm6nucijqq3vVHhbJIr~s1lqNBQ4a9I7C9uVE9khvJniXarLYw1gH-iC1F-xTWjUtUGV2sc3CzYxQh9mozZVbZAA0TiAwK0BEXOt368gWB7GTb34G2zJe3934AfCnfnAGPgzbQYCL9JsYaulvFJwjkk_&Key-Pair-Id=APKAI3N2VAFIZ34RBHFA

I need to know how to make the third triangle, printing only 1 character at a time, and nesting atleast one loop, all in under 11 lines of code (Excluding the def triangle():, and triangle() ) Can anyone help?

February 15th, 2013, 04:39 PM

eliskan

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The link doesn't seem to work.

February 15th, 2013, 04:41 PM

Jokus

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you have to get rid of the spaces in the : h t t p : / /

it wouldn't let me post a link in my first post

February 15th, 2013, 05:57 PM

b49P23TIvg

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The j (link) figure 3 triangle verb fits within the required number of lines.

Code:

   figure3triangle =: i. (< |)"0/ i:

   figure3triangle 8
1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 0 0 0 1 1 1 1 1 1 1
1 1 1 1 1 1 0 0 0 0 0 1 1 1 1 1 1
1 1 1 1 1 0 0 0 0 0 0 0 1 1 1 1 1
1 1 1 1 0 0 0 0 0 0 0 0 0 1 1 1 1
1 1 1 0 0 0 0 0 0 0 0 0 0 0 1 1 1
1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1
1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1

   '* ' ({~ figure3triangle) 8
        *        
       ***       
      *****      
     *******     
    *********    
   ***********   
  *************  
 ***************

We can make it work in python!

Code:

import operator                                                 # line 1
integers = lambda y: list(range(y) if 0 <= y else reversed(range(-y)))          ; assert integers(8) == [0, 1, 2, 3, 4, 5, 6, 7]
steps = lambda y: list(range(-y, y + ((0 <= y) - (y < 0)), (0 <= y) - (y < 0))) ; assert [3, 2, 1, 0, -1, -2, -3] == steps(-3)
dyadicHook = lambda f, g: lambda x, y: f(x, g(y))               # line 4
table = lambda u: lambda x, y: [[u(X,Y) for Y in y] for X in x] # line 5
monadicFork = lambda f, g, h: lambda y: g(f(y), h(y))           # line 6
figure3triangle = monadicFork(integers, table(dyadicHook(operator.lt, operator.abs)), steps) # figure3triangle is a function
BOOLEAN_ARRAY = figure3triangle(8)                              # line 8
for ROW in BOOLEAN_ARRAY:                                       # line 9
    print(''.join('* '[ATOM] for ATOM in ROW))                  # line 10
#print('\n'.join(''.join('* '[ATOM] for ATOM in ROW) for ROW in BOOLEAN_ARRAY))  # replacement for lines 9 and 10

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Last edited by b49P23TIvg : February 15th, 2013 at 06:04 PM.

February 15th, 2013, 09:37 PM

dwblas

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The following does it in seven lines but does not nest one loop (note Python 2.7 print statement)

Code:

triangle_height=8
spaces = " " * triangle_height
to_print = "#"
for ctr in range(triangle_height):
    print "%s%s" % (spaces, to_print)
    to_print += "##"
    spaces = spaces[1:]

So maybe something like the following. "Print one character at a time" could be done instead of packing the string if you suppress the space following and/or the new line of a normal print statement.

Code:

triangle_height=8
for ctr in range(triangle_height):
    spaces = ""
    for sp in range(ctr, triangle_height):
        spaces += " "
    stars = "*" + ("*" * ctr*2)     ## or a for() loop
    print "%s%s" % (spaces, stars)

Need help with this problem. ( Python 3.2.1.1)

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