Newbie question

def func1(a,b,c):
e = a + b/c
return formatted(e)

def func2(f,g,h,i):
j = func1(f,g,h) + i
return formatted(k)

def func3(f,g,h,i):
j = (f + g/h) + i
return formatted(j)


def formatted(a):
return ("$%.2f" % a)

When I run the below....

print(func1(1,2,3))
print(func2(1,2,3,4))
print(func3(1,2,3,2))


I get

Traceback
<module> D:\Python33\test.py 18
func2 D:\Python33\test.py 6
TypeError: Can't convert 'int' object to str implicitly


If I run this

print(func1(1,2,3))
print(func3(1,2,3,2))

it runs fine..

>>>
$1.67
$3.67


What Am I doing wrong, I need the func2 format to work especially with float as the last parameter.

Thanks for looking.

You can't add a float to a string.

Also, your func2 references a "k" variable does doesn't exist.

Hi I figured this out. I will post the solution in case it may help someone.

The return value from func1 is a string. You can not add float or int to a string. The return has to be converted to a float.

def func1(a,b,c):
e = a + b/c
return formatted(e)

def func2(f,g,h,i):

return formatted(j)

def func3(f,g,h,i):
j = (f + g/h) + i
return formatted(j)


def formatted(a):
return ("%.2f" % a)

print(func1(1,2,3))
print(func2(2,3,4,4))
print(func3(1,2,3,2))

This work fine.

Thanks sir, I think we were writing the answer at the same time.

Could you please tell me, how can I format the output like in my original post

Thanks

Your original function contained a $ character.


def formatted(a):

return ("$%.2f" % a)