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Output ls|awk to dict question
Hello,
I'm hoping someone might be able/willing to point me in the right direction to combat a small challenge I’m facing.
I'm pretty new to Python and already went thoroughly through "Learning Python (4th.ed)" and though this forum, but still not able to achieve the following:
I'm trying to create a dictionary in python3 based on the output of an awk'd ls command: ls -l | grep - | awk {'print $9","$5'}
The output from os.system("ls -l /bin | grep - | awk {'print $9\"=\" $5\",\"'}") seems to me to be the first step, but how to convert this to a dict is where i'm stuck..
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Quote:
Originally Posted by mik3nl
I'm trying to create a dictionary in python3 based on the output of an awk'd ls command: ls -l | grep - | awk {'print $9","$5'}
If I’m getting you right, the “grep -” part is there to get rid of the header line, $9 is the filename and $5 the file’s size. (BTW, you are relying on a specific formatting of ls’s output. If ls happens to be aliased or the localisation in use differs, for example, the field numbers might change.)
I think the smart way is to use Python all the way through:
Code:
import os
fileinfo = {}
for filename in os.listdir('.'):
fileinfo[filename] = os.stat(filename).st_size
Later on you could replace the '.' parameter with the contents of sys.argv, for instance.
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