Print 10 charaters from right in python

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Print 10 charaters from right in python

Hi,

I want to print 10 characters from right.

e.g. name="abcdef123456789asd"
i should be able to get o/p as "dsa9876543"

I tried the below method:

name = "abcdef123456789asd"
reverse= name[::-1] # This reverses the entire string
name=reverse[0:10]
print name

but believe there should be some other shorter way of doing it.
Request you to pls help.

Thanks
Siva

November 7th, 2012, 11:10 PM

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Code:

>>> 'abcdefghijklmnop'[-1:-11:-1]
'ponmlkjihg'
>>> len('abcdefghijklmnop'[-1:-11:-1])
10
>>> reversed('123')
<reversed object at 0xd32dd0>
>>> list(reversed('123'))
['3', '2', '1']
>>>

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November 7th, 2012, 11:17 PM

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Quote:

Originally Posted by b49P23TIvg

Code:

>>> 'abcdefghijklmnop'[-1:-11:-1]
'ponmlkjihg'
>>> len('abcdefghijklmnop'[-1:-11:-1])
10
>>> reversed('123')
<reversed object at 0xd32dd0>
>>> list(reversed('123'))
['3', '2', '1']
>>>

hi b49P23TIvg,

Thanks for your reply.. it works fine... can you pls explain how does this [-1:-11:-1] calculate to 10.

Thanks,
Siva

November 7th, 2012, 11:34 PM

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'ponmlkjihg'

10 == len( 'ponmlkjihg' )

November 7th, 2012, 11:37 PM

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Quote:

Originally Posted by b49P23TIvg

'ponmlkjihg'

10 == len( 'ponmlkjihg' )

I understood it.. Thanks.

November 7th, 2012, 11:48 PM

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Printing characters

I am new to python and trying out different things

a="abcdefghijklmnopqrst"

I want to print the last 10 characters i.e. klmnopqrst .. How do i do this?

Please let me know. Also , request you to suggest a good book for understanding python

Thanks
Siva

November 7th, 2012, 11:58 PM

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Code:

>>> #please try lots of slice tests on your own in the python interpreter
>>> A=list(range(20))
>>> A[1::2]  # odd
>>> A[::2]  # objects at even indexes
>>> A[:10]  # first 10 objects
>>> A[10:14] # objects 10, 11, 12, and 13

www.python.org find the tutorial. Read it and experiment in the python interpreter as you go.

November 8th, 2012, 12:03 AM

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Quote:

Originally Posted by b49P23TIvg

Code:

>>> #please try lots of slice tests on your own in the python interpreter
>>> A=list(range(20))
>>> A[1::2]  # odd
>>> A[::2]  # objects at even indexes
>>> A[:10]  # first 10 objects
>>> A[10:14] # objects 10, 11, 12, and 13

www.python.org find the tutorial. Read it and experiment in the python interpreter as you go.

Thanks mate!!!

November 10th, 2012, 05:20 PM

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LIST - search

Can you try this?
I have a list that says

Now I want to loop thru this and compare a value in a variable with the value of num in the above list. Any ideas??

Like my var may have 004, I need to check this against 'num' in the above list....

Thanks for the reply.... I think it should be

[('key1=1,t=US', {'Num': ['004'],'name': ['Roger'],'locCity': ['Oakbrook']}),
('key1=2,t=US', {'Num': ['005'],'name': ['Din'],'locCity': ['Brookside']})
]

Yes...Hope it makes sense now....
Thanks.

#10

November 10th, 2012, 07:25 PM

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You posted a syntax error. (Bad quotes, in my opinion.) What do you mean?

#11

November 10th, 2012, 07:39 PM

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That's correct...I have reposted.

#12

November 10th, 2012, 08:33 PM

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Code:

>>> var = '004'
>>> import pprint
>>> pprint.pprint(A)
[('key1=1,t=US', {'Num': ['004'], 'locCity': ['Oakbrook'], 'name': ['Roger']}),
 ('key1=2,t=US', {'Num': ['005'], 'locCity': ['Brookside'], 'name': ['Din']})]
>>> for L in A:
...  D = L[1]
...  for value in D.values():
...   if var in value:
...    print('found')
>>>

When structures get convoluted so that you need specialized functions to extract data you might do better with a class.

#13

November 10th, 2012, 10:07 PM

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Thanks very much. Appreciate your time.
Will try this code. Thanks...

#14

November 11th, 2012, 08:55 AM

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From the following LIST, I need to create a LIST or DICTIONARY where I need few fields from each row based on a match. Like I will get only 1 match at a time.

[('key1=1,t=US',
{'Num': ['004'], 'locCity': 'Oakbrook'], 'name': ['Roger'],'uid': [lname.fname@msn.com],'Date': [101010]}),
('key1=2,t=US',
{'Num': ['005'], 'locCity': ['Brookside'], 'name': ['Din'],'uid':[lname1.fname1@msn.com],'Date': [101110]}),
('key1=3,t=US',
{'Num': ['006'], 'locCity': ['OakBrook'], 'name': ['Dan'],'uid':[lname2.fname2@msn.com],'Date': [111010]})]

I have a string with lastname.firstname. With this I should loop thru the above tuples and for the matching entry, I have to store keys like Num, locCity and Date and their values. So I believe it should be a dictionary?.
Could it be done? Please advise.

#15

November 11th, 2012, 04:58 PM