Pyhton Loop

Hi
I am new to python infact programming. I am trying to write a programme which will pick 6 random numbers between 1 to 50 but no duplicate numbers and not using append function.

Here is something i wrote

import sys
import random
array=[]
#array=[55,65,1,89,10,54,1,258,2]
for i in range(5):

# storing Random numbers to an array
temp= random.randrange(1,50)
array+=[temp]
#print array

# random number(1-49) Validation (pick 6 different numbers) i #am stuck here
if temp == array[i]:
temp =random.randrange(1,50)
array+=[temp]

#Bubble sort(Ascending order)
for y in range(len(array)-1,0,-1):
for x in range(y):
if array[x]> array[x+1]:
array[x],array[x+1]=array[x+1],array[x]

# Displaying Random numbers in order (working)
for v in array:
print v,



Can someone help
Thanks
Luckyboy

Here's how I would do it, though I don't understand the restriction on not using .append()..



Normally instead of you'd just do as it's more efficient.

Hi it's working
Thank you strike

This problem is discussed at length in the book 'Programming Pearls' by Jon Bentley, which I recommend that anyone who is serious about programming should read.

Here is an alternative way. Create a list with the numbers 1-50 in it, shuffle it, and gets the first six elements



This is fine for a small list of 50, but if you wanted a random number from the set of 1..1,000,000,000, then it would create an array with a billion elements, and throw away a billion minus six of them. In that case I would go to the book I mentioned and use an alternative algorithm.

Dave - The Developers' Coach