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  #1  
Old December 8th, 2012, 10:10 AM
sravan18 sravan18 is offline
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Python code for a string program

HI!
could anyone help me out with the code for below question:

Given two strings, return True if either of the strings appears at the very end of the other string, ignoring upper/lower case differences (in other words, the computation should not be "case sensitive"). Note: s.lower() returns the lowercase version of a string.

end_other('Hiabc', 'abc') → True
end_other('AbC', 'HiaBc') → True
end_other('abc', 'abXabc') → True

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  #2  
Old December 8th, 2012, 04:53 PM
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Code:
>>> import pprint
>>> pprint . pprint ( dir ( '' ) )
['__add__',
 '__class__',
 ...
 'endswith',
 ...
 'zfill']
>>> 
__________________
[code]Code tags[/code] are essential for python code!

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  #3  
Old December 9th, 2012, 12:25 PM
dwblas dwblas is offline
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You can either reverse the letters in the words and check the beginning or convert to lists and start at -1 comparing letters.

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Old December 9th, 2012, 03:01 PM
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Code:
def end_other(x, y):
    return x[::-1][0:len(y)] == y[::-1]

case-insensitive:
Code:
def end_other(x, y):
    return (x[::-1][0:len(y)]).lower() == (y[::-1]).lower()

Last edited by AndrewSW : December 9th, 2012 at 03:04 PM.

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Old December 9th, 2012, 03:06 PM
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You don't seem to get it.

endswith is a string method.

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Old December 9th, 2012, 03:19 PM
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Quote:
Originally Posted by b49P23TIvg
You don't seem to get it.

endswith is a string method.

I suppose if this is homework they might not be expected to use a function, other than lower().. maybe len(). Although, my method is a bit cheeky

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Old December 9th, 2012, 03:23 PM
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Quote:
Originally Posted by dwblas
You can either reverse the letters in the words and check the beginning or convert to lists and start at -1 comparing letters.

Converting to lists is unnecessary as a string is already an iterable.

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