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  #1  
Old February 24th, 2013, 08:33 PM
TSZAR TSZAR is offline
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Python Help

Hi,
I've been working on a particular math-quiz game as an introductory project to python scripting. In this program, I use strings of random integers to create new problems every time a question comes up.

However, in one of these chains, the if-then statement that dictates what the program will do depending on if an answer is right or wrong has been malfunctioning. The statement completely bypasses the "correct" option and goes to the "incorrect" route (these are not hard either, its painfully obvious like 8+5=? questions)

The program piece that is malfunctioning looks like this:

import random
Qb=random.randint(1, 10)
Qbb=random.randint(1, 10)
print ('Question 2' + str (Qb) +' + ' + str (Qbb) + ' = ?')
Qba=input()
Qbaa = Qb + Qbb
if Qba == ('Qbaa'):
print ('Correct! + 25 to score!')
Score = Score + 25
print (Score)
else:
print ('Incorrect')

What is causing the correct path to be bypassed?

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  #2  
Old February 24th, 2013, 09:25 PM
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Code:
# python3
import random
Qb=random.randint(1, 10)
Qbb=random.randint(1, 10)
print ('Question 2:   ' + str (Qb) +' + ' + str (Qbb) + ' = ?') # separate the question number please!
Qba=input()      # Qba is a string
Qbaa = Qb + Qbb  # Qbaa is an integer
if Qba == str(Qbaa):   # compare as strings.   str(Qbaa)
    print ('Correct! + 25 to score!')
    Score = Score + 25
    print (Score)
else:
    print ('Incorrect')
__________________
[code]Code tags[/code] are essential for python code!

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Old February 24th, 2013, 10:07 PM
TSZAR TSZAR is offline
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Quote:
Originally Posted by b49P23TIvg
Code:
# python3
import random
Qb=random.randint(1, 10)
Qbb=random.randint(1, 10)
print ('Question 2:   ' + str (Qb) +' + ' + str (Qbb) + ' = ?') # separate the question number please!
Qba=input()      # Qba is a string
Qbaa = Qb + Qbb  # Qbaa is an integer
if Qba == str(Qbaa):   # compare as strings.   str(Qbaa)
    print ('Correct! + 25 to score!')
    Score = Score + 25
    print (Score)
else:
    print ('Incorrect')


Thank you for your help.

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