python loop2 - Dev Shed

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April 23rd, 2004, 06:33 PM

luckyboy

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python loop2

Hi
Can someone help me how to pick two set of 6 different random numbers . I tried but the while loop is not exititng.

Thanks in advance

Here is my code.

Code:

import sys
import random
array=[]
x=0
while x!=2: how to get multiple lines for 6 random numbers
 for i in range(6):
    temp=random.randrange(1,50)
    while temp in array:
        temp=random.randrange(1,50)
    array+=[temp]
 x+=1
 array.sort(cmp)
 for a in array:
  print array,

Last edited by luckyboy : April 29th, 2004 at 09:15 AM.

April 23rd, 2004, 06:57 PM

DevCoach

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firstly, please wrap your code in [code] tags. It will preserve the indentation, and not using it makes Python code virtually unreadable.

Secondly, what exactly do you mean by pick 6 different random numbers twice? Do you mean two sets of numbers without duplicates? Or two sets of random numbers, but there may be duplicates between sets? Or the same set, twice?

Dave - The Developers' Coach

April 24th, 2004, 05:27 AM

luckyboy

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Yes i mean 2 sets of 6 random numbers

April 24th, 2004, 05:42 AM

rebbit

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I would probably do it like this:

Code:

import random

rands = []
for x in range(2):
    rands.append([random.randrange(1, 51) for y in range(6)])

print rands

that will leave you with a list of sets of 6 random numbers, though you can probably work something out if you want it in a different structure.

April 24th, 2004, 06:40 AM

luckyboy

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Thanks

April 24th, 2004, 08:01 AM

luckyboy

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I tried your script even though the programme prints 2 set of 6 random numbers they are not unique. ie [2,2,34,5,32,21,12] [1,3,6,7,9,32,7]

April 26th, 2004, 07:07 AM

luckyboy

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Quote:

I have sorted the above problem and here is my code

Code:

import sys
    import random
    it=0
    ans=int(raw_input(" Enter Number of Set(s): "))
    print        
    while it !=ans:
     guess=[]
     while len(guess) !=6:#for x in range(6):
        temp=random.randrange(1,50)
        while temp in guess:
            temp=random.randrange(1,50)
        guess+=[temp]
     guess.sort(cmp)
     for y in guess:
        print "%3d" %(y),
     it+=1
     print

Luckyboy

Last edited by luckyboy : April 26th, 2004 at 07:32 AM.

April 26th, 2004, 09:58 AM

netytan

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Heres my version although i cant test it right now so this may not work in any case you should have no problems fixing the examples if they are broken

.. we'll see.

Code:

#!/usr/bin/env python

form random import sample

def randomNumbers():
    numbers = []
    for each in xrange(2):
        numbers.append(sample(xrange(1, 50), 6))
    return numbers

Code:

#!/usr/bin/env python

form random import sample

numbers = [sample(xrange(1, 50), 6) for each in range(2)]

This uses random.sample() to select 6 numbers from the xrange(1, 50) - the advantage of this is that every item should be unique. Although since this is being called twice it is possable that both lists may contain the same element. If this is a problem you could just do this...

Code:

#!/usr/bin/env python

form random import sample

def randomNumbers():
    numbers = sample(xrange(1, 50), 12)
    return (numbers[:6], numbers[7:])

Which will return a tuple of unique random numbers (unsorted) - if you do want these sorted then simply call sort() on the numbers list.

Hope this helps.

Mark.

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April 27th, 2004, 03:16 AM

luckyboy

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loops2

Thank you all

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