Python-Password - Dev Shed

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December 30th, 2012, 10:43 PM

OzzyTech

Registered User

Join Date: Dec 2012

Posts: 1

Time spent in forums: 16 m
Reputation Power: 0

Python-Password

I have this code I'm working on. I'm trying to go back to the start of the program and keep on going back to the start of the program until the user enters the right password. Does anyone know what the python code would be in order for me to do this? the program does not have to quit, I want the program to keep on asking the user "Enter your password" until the user puts in "letmein". then I would continue to the rest of the program.

see code below, this is what I have so far.

#Password
password=raw_input("Enter your password:")

if password == "letmein":
print "hey your in"
else:
print"Denied"
password=raw_input("Enter your password:")
print"try again"
password=raw_input("Enter your password:")
print"Sorry, you got to go now"
raw_input ("Press enter to exit")
quit()

December 31st, 2012, 08:14 AM

b49P23TIvg

Contributing User

Join Date: Aug 2011

Posts: 3,383

Time spent in forums: 1 Month 2 Weeks 3 Days 13 h 44 m 42 sec
Reputation Power: 383

Code:

import sys
for attempts in range(2):
    if 'some secret' == raw_input('password: '):
        break
    print('try again')
else:
    print('Pilot license revoked!')
    sys.exit(1)

print('<horse enter saloon>  Bartender: "Why the long face?"')

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January 2nd, 2013, 03:03 PM

Dietrich

Contributing User

Join Date: Feb 2005

Posts: 483

Time spent in forums: 3 Days 22 h 51 m 26 sec
Reputation Power: 63

Contributing User b49P23TIvg is correct, you really should limit the number of attempts to something reasonable.

You can rewrite your code like this:

Code:

#Password

limit_attempts = 5
attempts = 1
while True:
    password = raw_input("Enter your password: ")
    if password == "letmein":
        print "Hey your in!"
        break
    else:
        print "Denied, try again!"
    if attempts >= limit_attempts:
        print"Sorry, you got to go now!"
        break        
    attempts += 1
    

raw_input("Press enter to exit")

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