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Old April 21st, 2008, 10:23 AM
skeeter144 skeeter144 is offline
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Pythons regex look-behind is funky?

I have the following code:
Code:
string = "Hello      : Bob"
match = re.search(r"(?<=Hello.*:).*", string)
string = match.group()
print string


Returns this error:
Code:
sre_constants.error: look-behind requires fixed-width pattern


What gives?

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Old April 21st, 2008, 06:19 PM
OmegaZero OmegaZero is offline
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When in doubt, read the documentation:

Quote:
Originally Posted by 4.2.1 Regular Expression Syntax
Matches if the current position in the string is preceded by a match for ... that ends at the current position. This is called a positive lookbehind assertion. (?<=abc)def will find a match in "abcdef", since the lookbehind will back up 3 characters and check if the contained pattern matches. The contained pattern must only match strings of some fixed length, meaning that abc or a|b are allowed, but a* and a{3,4} are not. Note that patterns which start with positive lookbehind assertions will never match at the beginning of the string being searched; you will most likely want to use the search() function rather than the match() function:


Look-behind requires fixed-width pattern, your pattern contains the variable-width .* in the look behind. You need to write something like "Hello.*:(.*)" and extract the first group. (Or better, use split() on the colon)
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sub{*{$::{$_}}{CODE}==$_[0]&& print for(%:: )}->(\&Meh);

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