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#1
December 3rd, 2004, 09:52 PM
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Random Problem...
Whenever I try to call random.random or random.choice I get the following...
TypeError: 'module' object is not callable or AttributeError: 'module' object has no attribute 'choice' both of these come from previously working or examples I found on the web. Do I need to re-install python ?
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#2
December 3rd, 2004, 11:08 PM
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the function is random.randrange, random.random doesnt exist
if you want to use random.choice you need to give a group of elements to choose from to the frogram bye
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#3
December 3rd, 2004, 11:59 PM
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Hi,
Find below some of the tools belonging to the random module... can't figure out why u r getting such an error! But u cld try the following examples...n report if the problem still persists....what say?  Code:
>>> import random >>> for number in range(10): ... x=random.random() ... print x ... 0.435063217885 0.992538870884 0.653449999022 0.137293325169 0.12339139281 0.632875520517 0.835285602794 0.732443595278 0.353933184167 0.953251297425 >>> toons=['Dexter','Bubbles','DeeDee','ButterCup'] >>> random.choice(toons) 'Bubbles' >>> random.randrange(10) 1 >>> random.randrange(10) 3 >>> random.sample(range(40),5) [25, 38, 15, 29, 18] >>> All the abv are self explanatory...cld shed some light on random.sample... it will give you an unique list in the range provided.. Subha 
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#4
December 4th, 2004, 07:54 AM
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Unless you need the extra control you can get from random.randrange() I would probably use random.randint(), though it makes no real difference which you choose
.Code:
>>> import random >>> >>> random.randrange(0, 10) 4 >>> random.randrange(0, 10) 0 >>> random.randrange(0, 10) 8 >>> random.randrange(0, 10, 2) 8 >>> random.randrange(0, 10, 2) 0 >>> random.randrange(0, 10, 2) 2 >>> random.randint(0, 10) 10 >>> random.randint(0, 10) 2 >>> random.randint(0, 10) 4 >>> Note that the second set of calls to random.randrange() – the ones with the third argument – will only return even numbers from the range. Mark.
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