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#1
May 28th, 2004, 03:09 AM
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Range() Anomaly ?
Just curious about this.
 range(12) [0,1,2,3,4,5,6,7,8,9,10,11] (j,f,m,a,m,j,j,a,s,o,n,d)=range(12) j 6 j,j (6,6) j,j,j (6,6,6) Question: Why not "0" instead of 6?
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#2
May 28th, 2004, 04:00 AM
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the line (j,f,m,a,m,j,j,a,s,o,n,d)=range(12) is assigning to j multiple times. It is equivalent to
Code:
j = 0 f = 1 m = 2 a = 3 m = 4 j = 5 j = 6 etc... The earlier assignments to j are overwritten, so j will end up with the value of the last thing it is assigned to. What exactly do you want j to have? If you want it to contain a list of the values [0, 5, 6] then that can't be done directly. You can however create a dictionary with the letter as the key and a list of numbers as the values like this: Code:
>>> months = {}
>>> for index,month in enumerate('jfmamjjasond'): months.setdefault(month, []).append(index)
...
>>> months
{'a': [3, 7], 'd': [11], 'f': [1], 'j': [0, 5, 6], 'm': [2, 4], 'o': [9], 'n': [10], 's': [8]}
>>>
(N.B. this requires Python 2.3 or later). Dave - The Developers' Coach Last edited by DevCoach : May 28th, 2004 at 04:08 AM.
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#3
May 28th, 2004, 05:22 AM
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Very good!
Thanks for the explanation, as well as the programming hint. I think I am getting less dumb each day. James
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