Regular Expression

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April 20th, 2004, 08:29 PM

duniyadnd

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Regular Expression

I created a simple function to check for regular expressions, but it returns with no matches and I can't figure out what is wrong with it. Any help would be great. Thanks

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Code:

import urllib
import re

def Content(content):
  required = 'a'
  p = re.compile(required, re.IGNORECASE)
  #print content
  print "\n\nMatch is: \n"
  gr = p.match(content)
  print gr
  print "\n\nGroup is: \n"
  print gr.groups()

s = 'japana'
Content(s)

I keep getting "None" matches.

April 21st, 2004, 02:38 AM

DevCoach

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The problem is that regexObj.match() only matches at the start of the string. What you want to use is regexObj.search(), which will find the pattern anywhere in the string.

Also, if you use the matchObj.groups() method then you need to define at least one group in you pattern, e.g. '(a)', otherwise it will always return an empty tuple. If you just want to return the matched string then use matchObj.group().

Dave - The Developers' Coach

April 21st, 2004, 10:08 AM

duniyadnd

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Aaaaah, i should have mentioned that. I already tried group, and I had already put the paranthesis around 'a' as '(a)' but I still get "none" as matches

April 22nd, 2004, 11:14 AM

duniyadnd

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Figured out the problem when someone told me, that it was looking only for those letters, and not within the words.

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