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May 9th, 2004, 03:30 AM

xlordt

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socket error

Can anyone tell me what this means

Code:

Traceback (most recent call last):
  File "prog/proxy.py", line 15, in ?
    s.connect((ip, int(ports)))  #Connect to the given ip & port numbers
  File "<string>", line 1, in connect
  File "C:\Python23\lib\socket.py", line 143, in _dummy
    raise error(EBADF, 'Bad file descriptor')
socket.error: (9, 'Bad file descriptor')

What im tring to do is create a program that checks an ip/port and make sure its a working ip by connecting to it and receiving data( or do you have a better way )

Code:

from socket import *

fp        = open('c:\Python23\prog\data.txt', 'r')   #Open the file for reading.
read      = fp.read(1025)      #Read the file upto 1025 chars.
fp.close()
splits    = read.split('\n')   #Split the file according to the \n ( new line character ).

s = socket(AF_INET, SOCK_STREAM) #Start socket protocol.

for i in range(len(splits[:-1])):
    ip, ports = splits[i].split(':') #Create tuple of ips and ports.

    s.connect((ip, int(ports)))  #Connect to the given ip & port numbers
    s.send("GET \HTTP\1.1\r\n")
    received = s.recv(1025)
    s.close()
    
    print received, '\n'

Hopefully i wont figure it out before anyone postes

May 9th, 2004, 07:00 AM

DevCoach

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print out the strings read from the text file. I suspect that the problem is that the address has 'http://' at the start:

Code:

>>> from socket import *
>>> s = socket(AF_INET, SOCK_STREAM)
>>> s.connect(('www.python.org', 80))
>>> s.close()
>>> s.connect(('http://www.python.org', 80))
Traceback (most recent call last):
  File "<interactive input>", line 1, in ?
  File "<string>", line 1, in connect
  File "C:\dev\Python23\lib\socket.py", line 143, in _dummy
    raise error(EBADF, 'Bad file descriptor')
error: (9, 'Bad file descriptor')

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May 9th, 2004, 07:05 AM

DevCoach

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Ignore the previous post - I was wrong. The problem is that you close the socket, then do another connect call on it. Once you close the socket then it is dead - you have to create a new one.

Code:

>>> s.connect(('www.python.org', 80))
>>> s.close()
>>> s.connect(('www.python.org', 80))
Traceback (most recent call last):
  File "<interactive input>", line 1, in ?
  File "<string>", line 1, in connect
  File "C:\dev\Python23\lib\socket.py", line 143, in _dummy
    raise error(EBADF, 'Bad file descriptor')
error: (9, 'Bad file descriptor')
>>>

You do also get an error if you have 'http://' at the start of the URL, but it throws a different exception:

Code:

>>> s = socket(AF_INET, SOCK_STREAM)
>>> s.connect(('http://www.python.org', 80))
Traceback (most recent call last):
  File "<interactive input>", line 1, in ?
  File "<string>", line 1, in connect
gaierror: (7, 'getaddrinfo failed')

Dave - The Developers' Coach

May 9th, 2004, 03:27 PM

xlordt

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yes all of that i know, see what im tring to do is loop through some ips to check them and make sure it works.. if it does work then continue to the next one if it doesnt work then show [no good] and continue, what is the best recommendation for me to do this

Last edited by xlordt : May 9th, 2004 at 03:45 PM.

May 10th, 2004, 08:20 AM

sfb

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"My socket code is raising an exception, help"

"You're closing the socket, then trying to connect it again. You can't do that - when closed, a socket is dead. You have to make a new one."

"Yes, I know all that. How can I make my program work?"

May 10th, 2004, 09:08 AM

netytan

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Basically what needs to be done here is to put the whole socket handleing bit inside a loop. This way your creating a new socket for each check and your closing it at the end of the loop. you can then use a simple if to check if the socket connects successfully since i believe the connect() method returns a False value if the connection is refused

.

If not then you can always use a try-except block to do roughly the same thing.

Are you getting an error from every IP or just the closed ones? In any case you should defintly include a check to see if the connection was accepted if you can

Hope this helps some,

Mark.

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May 10th, 2004, 09:13 AM

xlordt

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Quote:

Originally Posted by sfb

hah? sfb your getting it wrong, the program i can do, just the looping part that is messed do you know what is really wrong??

netytan: no just the closed ones.. that code i posted was the wrong code.. kinda sorry.. here is the actual code

Code:

from socket import *
class MySock:

      def __init__(self, host, ip):

           self.con = socket(AF_INET, SOCK_STREAM)
           try:
                  if self.con.connect((host, int(ip))):
                     print '%s:%s  --  Good' % ( host, ip )
                  else:
                     raise Exception, 'skipping to Bad Message'
                  self.con.close()
           except:
                 print '%s:%s  --  Bad' % ( host, ip )
           self.con.close()


for x in file('c:\Python23\prog\proxy.txt'):

    (hosts, ips) = x.split(':')
    Tcp = MySock(hosts, ips)

what i want it to do is if the ip is closed then continue to the next

Last edited by xlordt : May 10th, 2004 at 10:11 AM.

May 10th, 2004, 09:25 AM

netytan

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Not sure how your file is organised but you might try checking the input being passed to your class. Also not thinking you really need to be using a class here - you might try changing to a function just for preformance and style reasons.

Can you give up a few example lines for your program?

Mark.

May 10th, 2004, 09:42 AM

netytan

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here's a revised version...

Code:

from socket import *

def hostest(host, port):
    basesocket = socket(AF_INET, SOCK_STREAM)
    try:
        basesocket.connect((host, int(port))):
        print '%s:%s - Good' % (host, port)
        basesocket.close()
    except:
        print '%s:%s - Bad' % (host, port)

for line in file('c:\Python23\prog\data.txt'):
    host, port = line.split(':')
    hostest(host, port)

Note: this is untested as of yet but it should work in theory

.

Mark.

Last edited by netytan : May 10th, 2004 at 10:11 AM.

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