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  #1  
Old November 9th, 2012, 11:29 PM
emo.vs.elmo emo.vs.elmo is offline
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I just need help

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Old November 10th, 2012, 09:38 AM
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default dictionaries would be useful, though not necessary. You can learn about them here.

Given the amazing clue that you can convert an iterable to a tuple using tuple the keys of this dictionary are given by

for i in drink_list:
key = tuple(i)

tuples are immutable. That means they cannot be changed. Therefor the hash function always returns the same value. That's why tuples, but not lists, can be used as dictionary keys.


You might also use the generic pattern:

container = EmptyContainer()
loop:
update(container,newInformation)
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[code]Code tags[/code] are essential for python code!

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Old November 10th, 2012, 12:51 PM
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??

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Old November 10th, 2012, 01:12 PM
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I can't think of how to say more without completely writing the function. There's not much to it.

Can you start the python interpreter? Is python installed on your computer? Find the distribution at www.python.org .

What does python respond if you type in "'hi'" ?

Can you get python to import a module? Here's an experiment to prove yourself.
Get python to show you the value of the hexdigits variable in the string module.

Am I pissing you off with these pathetic questions? Good, you're ready to go. The program you're assigned is not much harder.

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Old November 10th, 2012, 01:23 PM
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PS. The doctest of your function, which you'd run on the command line with
python -m doctest -v my_python_source.py
reads
>>> build_ranking_to_frequency([['cola', 'beer', 'coffee', 'tea'], ['cola', 'beer', 'tea', 'coffee'], ['cola', 'beer', 'coffee', 'tea']])
{('cola', 'beer', 'coffee', 'tea'): 2, ('cola', 'beer', 'tea', 'coffee'): 1}

If you study dictionaries long enough and practice with them in glorious variation you'll discover---you must discover---that the output of build_ranking_to_frequency is a dictionary.

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Old November 10th, 2012, 01:40 PM
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I am a comp major so yes i do have python visualizer and i know that i have to output a dictionary.

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