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#1
November 1st, 2012, 10:26 PM
 nasicode
Registered User

Join Date: Nov 2012
Posts: 7
Time spent in forums: 1 h 39 m 24 sec
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Why is it that the confidence of the second tuple in L not calculated?

Code:
```supportData = {('nas','fat'): 0.5, ('nas'): 1.0, ('fat'):0.6, ('van'):0.72, ('jos'):0.55,('van','jos'):0.10}

L = [('nas','fat'),('van','jos')]

#for i in L:
for freqSet in L:#only get the sets with two or more items
H = [''.join(list(i)) for i in freqSet]

for conseq in H:
print H
freqsetlist = list(freqSet)
freqsetlist.remove(conseq)
print freqsetlist
conf = supportData[freqSet]/supportData[tuple(freqsetlist)[0]]
if conf >= 0.5:
print freqsetlist,'-->',conseq,'conf:',conf```

If I run the code I get:
Code:
```['nas', 'fat']
['fat']
['fat'] --> nas conf: 0.833333333333
['nas', 'fat']
['nas']
['nas'] --> fat conf: 0.5
['van', 'jos']
['jos']
['van', 'jos']
['van']```

#2
November 1st, 2012, 11:26 PM
 b49P23TIvg
Contributing User

Join Date: Aug 2011
Posts: 4,158
Time spent in forums: 1 Month 3 Weeks 2 Days 9 h 8 m
Reputation Power: 455
Given that your program doesn't work, and that I couldn't find the result you anticipated, I've modified your program to print better diagnostic information. First, you have this overly complicated statement
H = [''.join(list(i)) for i in freqSet]
which is equivalent to
H = list(freqSet)
making me think the program doesn't do what you expect.
Code:
```supportData = {('nas','fat'): 0.5, ('nas'): 1.0, ('fat'):0.6, ('van'):0.72, ('jos'):0.55,('van','jos'):0.10}

L = [('nas','fat'),('van','jos')]

for freqSet in L: #only get the sets with two or more items
H = list(freqSet)
for conseq in H:
freqsetlist = list(freqSet)
freqsetlist.remove(conseq)
print'numerator   key:value  == %s:%f'%(freqSet,supportData[freqSet])
key = tuple(freqsetlist)[0]
print'denominator key:value  == %s:%f'%(key,supportData[key])
conf = supportData[freqSet]/supportData[tuple(freqsetlist)[0]]
if conf >= 0.5:
print freqsetlist,'-->',conseq,'conf:',conf```

Run:
Code:
```\$ ( cd /tmp && python q.py )
numerator   key:value  == ('nas', 'fat'):0.500000
denominator key:value  == fat:0.600000
['fat'] --> nas conf: 0.833333333333
numerator   key:value  == ('nas', 'fat'):0.500000
denominator key:value  == nas:1.000000
['nas'] --> fat conf: 0.5
numerator   key:value  == ('van', 'jos'):0.100000
denominator key:value  == jos:0.550000
numerator   key:value  == ('van', 'jos'):0.100000
denominator key:value  == van:0.720000```
__________________
[code]Code tags[/code] are essential for python code!

#3
November 2nd, 2012, 01:02 AM
 nasicode
Registered User

Join Date: Nov 2012
Posts: 7
Time spent in forums: 1 h 39 m 24 sec
Reputation Power: 0
Quote:
 Originally Posted by b49P23TIvg Given that your program doesn't work, and that I couldn't find the result you anticipated, I've modified your program to print better diagnostic information. First, you have this overly complicated statement H = [''.join(list(i)) for i in freqSet] which is equivalent to H = list(freqSet) making me think the program doesn't do what you expect. Code: ```supportData = {('nas','fat'): 0.5, ('nas'): 1.0, ('fat'):0.6, ('van'):0.72, ('jos'):0.55,('van','jos'):0.10} L = [('nas','fat'),('van','jos')] for freqSet in L: #only get the sets with two or more items H = list(freqSet) for conseq in H: freqsetlist = list(freqSet) freqsetlist.remove(conseq) print'numerator key:value == %s:%f'%(freqSet,supportData[freqSet]) key = tuple(freqsetlist)[0] print'denominator key:value == %s:%f'%(key,supportData[key]) conf = supportData[freqSet]/supportData[tuple(freqsetlist)[0]] if conf >= 0.5: print freqsetlist,'-->',conseq,'conf:',conf``` Run: Code: ```\$ ( cd /tmp && python q.py ) numerator key:value == ('nas', 'fat'):0.500000 denominator key:value == fat:0.600000 ['fat'] --> nas conf: 0.833333333333 numerator key:value == ('nas', 'fat'):0.500000 denominator key:value == nas:1.000000 ['nas'] --> fat conf: 0.5 numerator key:value == ('van', 'jos'):0.100000 denominator key:value == jos:0.550000 numerator key:value == ('van', 'jos'):0.100000 denominator key:value == van:0.720000```

But the confidence for tuple ('van','jos') hasn't been calculated like that of ('nas','fat'). The question is, what is stopping the the confidence calculation for the second tuple ?

#4
November 2nd, 2012, 01:21 AM
 b49P23TIvg
Contributing User

Join Date: Aug 2011
Posts: 4,158
Time spent in forums: 1 Month 3 Weeks 2 Days 9 h 8 m
Reputation Power: 455
nothing's stopping the calculation.
10/55 is less than a half,
10/72 is also less than a half.
This statement prevents them from printing:
Code:
```        if conf >= 0.5:
print freqsetlist,'-->',conseq,'conf:',conf```

#5
November 2nd, 2012, 02:15 AM
 nasicode
Registered User

Join Date: Nov 2012
Posts: 7
Time spent in forums: 1 h 39 m 24 sec
Reputation Power: 0
Quote:
 Originally Posted by b49P23TIvg nothing's stopping the calculation. 10/55 is less than a half, 10/72 is also less than a half. This statement prevents them from printing: Code: ``` if conf >= 0.5: print freqsetlist,'-->',conseq,'conf:',conf```

Poor me! Thank you. I am very grateful

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