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Why is it that the confidence of the second tuple in L not calculated?


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  #1  
Old November 1st, 2012, 09:26 PM
nasicode nasicode is offline
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Why is it that the confidence of the second tuple in L not calculated?
Code:
supportData = {('nas','fat'): 0.5, ('nas'): 1.0, ('fat'):0.6, ('van'):0.72, ('jos'):0.55,('van','jos'):0.10}

L = [('nas','fat'),('van','jos')]

#for i in L:
for freqSet in L:#only get the sets with two or more items
    H = [''.join(list(i)) for i in freqSet]
    
    for conseq in H:
        print H
        freqsetlist = list(freqSet)
        freqsetlist.remove(conseq)
        print freqsetlist
        conf = supportData[freqSet]/supportData[tuple(freqsetlist)[0]]
        if conf >= 0.5:
              print freqsetlist,'-->',conseq,'conf:',conf


If I run the code I get:
Code:
['nas', 'fat']
['fat']
['fat'] --> nas conf: 0.833333333333
['nas', 'fat']
['nas']
['nas'] --> fat conf: 0.5
['van', 'jos']
['jos']
['van', 'jos']
['van']
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  #2  
Old November 1st, 2012, 10:26 PM
b49P23TIvg's Avatar
b49P23TIvg b49P23TIvg is offline
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Given that your program doesn't work, and that I couldn't find the result you anticipated, I've modified your program to print better diagnostic information. First, you have this overly complicated statement
H = [''.join(list(i)) for i in freqSet]
which is equivalent to
H = list(freqSet)
making me think the program doesn't do what you expect.
Code:
supportData = {('nas','fat'): 0.5, ('nas'): 1.0, ('fat'):0.6, ('van'):0.72, ('jos'):0.55,('van','jos'):0.10}

L = [('nas','fat'),('van','jos')]

for freqSet in L: #only get the sets with two or more items
    H = list(freqSet)
    for conseq in H:
        freqsetlist = list(freqSet)
        freqsetlist.remove(conseq)
        print'numerator   key:value  == %s:%f'%(freqSet,supportData[freqSet])
        key = tuple(freqsetlist)[0]
        print'denominator key:value  == %s:%f'%(key,supportData[key])
        conf = supportData[freqSet]/supportData[tuple(freqsetlist)[0]]
        if conf >= 0.5:
              print freqsetlist,'-->',conseq,'conf:',conf


Run:
Code:
$ ( cd /tmp && python q.py )
numerator   key:value  == ('nas', 'fat'):0.500000
denominator key:value  == fat:0.600000
['fat'] --> nas conf: 0.833333333333
numerator   key:value  == ('nas', 'fat'):0.500000
denominator key:value  == nas:1.000000
['nas'] --> fat conf: 0.5
numerator   key:value  == ('van', 'jos'):0.100000
denominator key:value  == jos:0.550000
numerator   key:value  == ('van', 'jos'):0.100000
denominator key:value  == van:0.720000
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  #3  
Old November 2nd, 2012, 12:02 AM
nasicode nasicode is offline
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Quote:
Originally Posted by b49P23TIvg
Given that your program doesn't work, and that I couldn't find the result you anticipated, I've modified your program to print better diagnostic information. First, you have this overly complicated statement
H = [''.join(list(i)) for i in freqSet]
which is equivalent to
H = list(freqSet)
making me think the program doesn't do what you expect.
Code:
supportData = {('nas','fat'): 0.5, ('nas'): 1.0, ('fat'):0.6, ('van'):0.72, ('jos'):0.55,('van','jos'):0.10}

L = [('nas','fat'),('van','jos')]

for freqSet in L: #only get the sets with two or more items
    H = list(freqSet)
    for conseq in H:
        freqsetlist = list(freqSet)
        freqsetlist.remove(conseq)
        print'numerator   key:value  == %s:%f'%(freqSet,supportData[freqSet])
        key = tuple(freqsetlist)[0]
        print'denominator key:value  == %s:%f'%(key,supportData[key])
        conf = supportData[freqSet]/supportData[tuple(freqsetlist)[0]]
        if conf >= 0.5:
              print freqsetlist,'-->',conseq,'conf:',conf


Run:
Code:
$ ( cd /tmp && python q.py )
numerator   key:value  == ('nas', 'fat'):0.500000
denominator key:value  == fat:0.600000
['fat'] --> nas conf: 0.833333333333
numerator   key:value  == ('nas', 'fat'):0.500000
denominator key:value  == nas:1.000000
['nas'] --> fat conf: 0.5
numerator   key:value  == ('van', 'jos'):0.100000
denominator key:value  == jos:0.550000
numerator   key:value  == ('van', 'jos'):0.100000
denominator key:value  == van:0.720000




But the confidence for tuple ('van','jos') hasn't been calculated like that of ('nas','fat'). The question is, what is stopping the the confidence calculation for the second tuple ?
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  #4  
Old November 2nd, 2012, 12:21 AM
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b49P23TIvg b49P23TIvg is offline
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nothing's stopping the calculation.
10/55 is less than a half,
10/72 is also less than a half.
This statement prevents them from printing:
Code:
        if conf >= 0.5:
              print freqsetlist,'-->',conseq,'conf:',conf
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  #5  
Old November 2nd, 2012, 01:15 AM
nasicode nasicode is offline
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Quote:
Originally Posted by b49P23TIvg
nothing's stopping the calculation.
10/55 is less than a half,
10/72 is also less than a half.
This statement prevents them from printing:
Code:
        if conf >= 0.5:
              print freqsetlist,'-->',conseq,'conf:',conf





Poor me! Thank you. I am very grateful
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