[Yegg`]

I've having a bit of a problem doing something in Python that Visual Basic 6 has the capability of. I need Python to do:

int('0x' + '1234567890123'[:3])

I just made up a number with the correct length. Python will return the following error:

Traceback (most recent call last):
  File "<pyshell#26>", line 1, in ?
    int('0x')
ValueError: invalid literal for int(): 0x

I want Python to return:

>>> 0x123
291

But, I can do:

>>> 0x+int('1234567890123'[:3])
123

The problem is that Python isn't returning 291. I don't already know what the number is going to be, so there's no way to automatically know the first three digits of it. Is there another way to doing this?

[jacktasia]

i don't know if this is the best way to do this but it works

>>>eval("0x"+'1234567890123'[:3])
291

[Yegg`]

Thanks a lot jacktasia. This works just fine.

[hydroxide]

Originally Posted by †Yegg†

The problem is that Python isn't returning 291. I don't already know what the number is going to be, so there's no way to automatically know the first three digits of it. Is there another way to doing this?

int("123", 16)
hex(291)

--OH.

[Yegg`]

Oh. That works too.