[vincent.pinzon]

Hello,

I have a script, which compares 2 directories, and performs a copy function. In this I have a source dir and a dest dir, and I am comparing both these. Now, I need to enhance this a bit. What if, I have multiple dest dir's and 1 source dir.
I need the single source dir, to be compared with all the dest dir's one by one and perform the copy function. I tried using the loop, but i messing it up. Can you guys help out.
Here's what I have,

import os.path
import os
import shutil

source = r'\Path1'
dest = r'Path\2'

sourcefiles = {os.path.splitext(x)[0] for x in os.listdir(source) if os.path.splitext(x)[1] == '.ext1'}
destfiles = {os.path.splitext(x)[0] for x in os.listdir(source) if os.path.splitext(x)[1] == '.ext2'}

print os.getcwd()

for missing in sourcefiles - destfiles:   # calculate the difference
    sourcefile = os.path.join(source, missing + '.ext2')
    destfile = os.path.join(dest, missing + '.ext2')
    shutil.copy(sourcefile, destfile)

[rrashkin]

Originally Posted by vincent.pinzon

Hello,

I have a script, which compares 2 directories, and performs a copy function. In this I have a source dir and a dest dir, and I am comparing both these. Now, I need to enhance this a bit. What if, I have multiple dest dir's and 1 source dir.
I need the single source dir, to be compared with all the dest dir's one by one and perform the copy function. I tried using the loop, but i messing it up. Can you guys help out.
Here's what I have,

import os.path
import os
import shutil

source = r'\Path1'
dest = r'Path\2'

sourcefiles = {os.path.splitext(x)[0] for x in os.listdir(source) if os.path.splitext(x)[1] == '.ext1'}
destfiles = {os.path.splitext(x)[0] for x in os.listdir(source) if os.path.splitext(x)[1] == '.ext2'}

print os.getcwd()

for missing in sourcefiles - destfiles:   # calculate the difference
    sourcefile = os.path.join(source, missing + '.ext2')
    destfile = os.path.join(dest, missing + '.ext2')
    shutil.copy(sourcefile, destfile)

First of all, I don't know what using {} in what appears to be a list and not a dictionary does. I think it should fail.

Second, you use "source" in both lists and I think you want to use "dest" in building "destfiles".

So now, what if "dest" were a list:

dests=["path2","path3","path4"]

note the "s"...dests.

Wrap the entire process, from "sourcefiles=..." to the end, in a loop:

for dest in dests:

[vincent.pinzon]

Originally Posted by rrashkin

First of all, I don't know what using {} in what appears to be a list and not a dictionary does. I think it should fail.

Second, you use "source" in both lists and I think you want to use "dest" in building "destfiles".

So now, what if "dest" were a list:

dests=["path2","path3","path4"]

note the "s"...dests.

Wrap the entire process, from "sourcefiles=..." to the end, in a loop:

for dest in dests:

Yes, I have used source in both of them, and yes you are right about that. the script works fine, I have it tested.

Now,

dests=["path2","path3","path4"]

I can do this only if the list is static, first of all the list is dynamic, it keeps changing and second I'm trying to put this in a loop, so that, when I run the script, it visits each folder, and performs the copy function.

Say, I have 6 folders, now the

dest = r'Path\2'

needs to be in a loop right, somehow! I'm just going wrong with the logic

[b49P23TIvg]

$ python3
Python 3.2.3 (default, Oct 19 2012, 19:53:16) 
[GCC 4.7.2] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> type({1,2,3})
<class 'set'>
>>>

[rrashkin]

Originally Posted by b49P23TIvg

$ python3
Python 3.2.3 (default, Oct 19 2012, 19:53:16) 
[GCC 4.7.2] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> type({1,2,3})
<class 'set'>
>>>

I didn't know that (I always used set(list)). Is this new to v3 or has it always been there and I just didn't know?

[b49P23TIvg]

Without investigating the subject, I recall that the set and tuple comprehensions were new in python 3000 also known as python3k now known as python3. I expect they'd also be part of python2.7 since the syntax doesn't break any code. I ignored python 2.6.

>>> {i**2 for i in range(-4,5)} # set comprehension
set([16, 9, 4, 0, 1])
>>> 
>>> 
>>> 
>>> def f(iterator):
...     for i in iterator:
...         print(i,i*i)
... 
>>> 
>>> 
>>> 
>>> f(i*i for i in range(4))  # (I think) this is called tuple comprehension
(0, 0)
(1, 1)
(4, 16)
(9, 81)
>>> 
>>> 
>>> 
>>> sys.version
'2.7.3 (default, Sep 26 2012, 21:51:14) \n[GCC 4.7.2]'