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Preg_replace to turn $12\\\\\\.50 = $12.50
Discuss Preg_replace to turn $12\\\\\\.50 = $12.50 in the Regex Programming forum on Dev Shed.
Preg_replace to turn $12\\\\\\.50 = $12.50 Regular expressions forum covering PCRE and POSIX techniques, practices, and standards. Regular expressions help shorten coding time by providing the ability to compact many lines of code into one string.
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February 5th, 2009, 05:12 PM
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Preg_replace to turn $12\\\\\\.50 = $12.50
Hi
Can anyone show me the correct preg_replace regular expression to match "\\\\\\." with 1 or more digits on either side?
my current version below cuts off whatever digit is directly to the left of the "." for some reason - ie. it turns 15\\\\\\.50 into 1.50
Code:
$string = preg_replace("/[0-9](\\\{6}\.)[0-9]/",".",$string);
Regan
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February 5th, 2009, 06:00 PM
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Psycho Canadian
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Join Date: Jan 2001
Location: Canada
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Try this
PHP Code:
$string = '15\\\\\\.50';
$string = preg_replace("/([0-9]+)\\\+\.([0-9]+)/", "$1.$2", $string);
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February 5th, 2009, 06:56 PM
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Quote: | Originally Posted by Viper_SB
PHP Code:
$string = '15\\\\\\.50';
$string = preg_replace("/([0-9]+)\\\+\.([0-9]+)/", "$1.$2", $string);
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Nope, that deletes the digits on both sides. :|
I just want to "replace" the "\\\\\\." with "." if it has a digit on both sides of it.
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February 5th, 2009, 07:01 PM
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Still alive
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Join Date: Mar 2007
Location: Washington, USA
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Quote: | Originally Posted by ryel01 Nope, that deletes the digits on both sides. :| |
I just tried it and it works fine.
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February 5th, 2009, 07:05 PM
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Quote: | Originally Posted by requinix I just tried it and it works fine. |
Ahh you're right, sorry I missed the "$1.$2" when pasting it into my page.
WORKS PERFECTLY!!!
Thanks requinix! 
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February 5th, 2009, 07:27 PM
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Still alive
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Join Date: Mar 2007
Location: Washington, USA
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Quote: | Originally Posted by ryel01 Thanks requinix! |
Me? Thank Viper, all I did was check that it worked.
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February 5th, 2009, 11:26 PM
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Ah, it's been a long day and night.
Thanks Viper_SB!
Regan
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