Regex pattern

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February 1st, 2013, 11:32 AM

Black_Hat

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Regex pattern

What is the regex pattern which replace every word "car" with "bar" in the first set and the second does not?

First:

Code:

car dog 680
baby car bottle
!@#$%^ car 987654
WHISPER book car
q  car ^&&* ;yu

Second:

Code:

car dog 680 hh
baby car bottle hh
!@#$%^ car 987654 hh
WHISPER book car hh
q  car ^&&* ;yu hh

February 1st, 2013, 12:40 PM

requinix

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What? Do you want to replace car->bar or not?

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February 1st, 2013, 02:05 PM

Black_Hat

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I want replace car with something (It's an example) but only if at the end there is no "hh".

Effect should be like:

Code:

bar dog 680
baby bar bottle
!@#$%^ bar 987654
WHISPER book bar
q  bar ^&&* ;yu
car dog 680 hh
baby car bottle hh
!@#$%^ car 987654 hh
WHISPER book car hh
q  car ^&&* ;yu hh

February 1st, 2013, 03:14 PM

requinix

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You can't do this with one expression: you'll need some code to back it.

Since you need code,
1. Grab a line
2. If the line ends in "hh" then goto 1
3. Replace every "car" with "bar"
4. Goto 1 until you reach the end of the file

February 1st, 2013, 03:58 PM

Black_Hat

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Is it impossible to do it in one step (one pattern which exclude lines with "hh" at the end?)?

February 1st, 2013, 04:39 PM

requinix

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Well... no, on second thought you can. The problem is the possibility of there being more than one "car" on a line, but that's not necessarily a problem.

Assuming PCRE,

Code:

/\bcar\b(?!.*hh$)/

(\b is a word boundary, otherwise it would match "cartel" too)

I just don't like doing replacements this way. It's valid, but it feels weird to me so I rarely ever consider it.

February 1st, 2013, 06:17 PM

Black_Hat

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Thank You very much!

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