Return from leftmost match of string.

Hi.

Given a string like:
"Hallo da. Ich bin Rolf. Ich arbeite hier. Tolle Sache."

How would I replace everything up to, but not including "Ich (arbeite|bin)"?

I tried:
gsub(".*?Ich (arbeite|bin)","",$0); print$0}

which returns "hier. Tolle Sache."

How do I:
1) Return the "Ich arbeite/Ich bin" part as well?
2) Return from the first occurence of "Ich (arbeite|bin)", not the last. In this case, I'd want to return "Ich bin Rolf. Ich arbeite hier. Tolle Sache."

Thank you.

You could use grep, For example:

Code:

echo "Hallo da. Ich bin Rolf. Ich arbeite hier. Tolle Sache." | grep -Go '\(Ich.\{1,\}\)\(Ich.\{0,\}\)'
Ich bin Rolf. Ich arbeite hier. Tolle Sache.

Thanks. Given that I wanted this in an awk script, I couldn't straightforwardly use grep. Your comment, however, did make me realize that grepping, rather than subbing was the right thing to do.

This seems to work fine now: