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  #1  
Old January 24th, 2012, 05:45 AM
cafelatte cafelatte is offline
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Simple regular expression

In my string '$string', I want to replace every instance of ". [A-Z]",

i.e., a full stop, followed by a space, followed by a capital later

with ".<br><br>[A-Z]"

but I'm such a numpty when it comes to regular expressions.

Help!

Edit: Oops, I wonder if some good-natured soul would be so kind as to move my thread to the regex forum 'which we now have'!!!

Thanks

Last edited by cafelatte : January 24th, 2012 at 06:31 AM.

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Old January 24th, 2012, 08:31 AM
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Done. Thanks for noticing.

Search on
Code:
/. ([A-Z])/

Use $1 to insert the letter back into the replacement string, since that's the only variable part of the whole thing.

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Old January 24th, 2012, 11:56 AM
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Hi cafelatte,

I'd suggest one tiny change from Requinix's suggestion because you want to match a literal period, not a "dot" (any character).

I have tested this php.

Input:
Period. Again.One.Word. Hi.5.33

Code:
PHP Code:
<?php
$regex
=',\. ([A-Z]),';
$string='Period. Again.One.Word. Hi.5.33';
echo 
htmlentities(preg_replace($regex,'.<br /><br />\1',$string));
?>


Output:
Period.<br /><br />Again.One.Word.<br /><br />Hi.5.33

The htmlentities is just for display, what you want is the preg_replace.

Let us know if one of those works for you.
:-)
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Last edited by ragax : January 27th, 2012 at 08:32 PM. Reason: Inserted space char in the regex

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