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#1
July 3rd, 2009, 04:19 AM
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Searching and replacing in a string based character occurence
Hey,
I have an IP address and I need to manipulate the final octet in a few different ways. For example, I have: Code:
str = 10.100.100.0 And I want to end up with: Code:
newStr1 = 10.100.100. Code:
newStr2 = 10.100.100.1 Now the IP address length may vary so I can't spilt up on string length, I need to split up after the 3rd occurence of '.' . In PHP I'd use substr_replace but I can't find a Ruby equivilant. Any ideas? Thanks!
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#2
July 3rd, 2009, 09:25 PM
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Code:
irb(main):001:0> s = "10.1.1.1" => "10.1.1.1" irb(main):002:0> a = s.split '.' => ["10", "1", "1", "1"] irb(main):003:0> a => ["10", "1", "1", "1"] irb(main):004:0> a[3] = "200" => "200" irb(main):005:0> a.join '.' => "10.1.1.200" Or you can use ruby's 'intelligence' to your advantage: Code:
irb(main):001:0> s = "10.1.1.1" => "10.1.1.1" irb(main):002:0> s.next => "10.1.1.2"
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