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#1
November 18th, 2005, 03:36 AM
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awk program - Skip first & last record
Hi All,
I am parsing a pipe separated input file (PSV) with Pipe as a pattern. I need to skip the first & last record from the file while parsing. Please note that, newline ('\n') is the record separator. Please let me know how do I skip first & last records (they are header & footer records). Thanks, BSP
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#2
November 18th, 2005, 05:22 PM
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you did not give us a clue about how to identify these records, so this is as good as it gets:
Code:
awk -V var=`cat filename | wc -l` ' NR > 1 && NR < var ' filename
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#3
November 19th, 2005, 05:12 AM
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why not a little logic
Code:
init a savedline to NULL
while read line{
print the saved line if not NULL # skip THE FIRST LINE
save the line to savedline
}
# skip THE LAST LINE
that's all
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