Awk: display all fields but one

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September 14th, 2006, 01:59 AM

Verletto

Registered User

Join Date: May 2006

Location: Sweden

Posts: 14

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Awk: display all fields but one

Hi all

Just say you have a line containing 50 delimited fields. Is there a quick way I could tell awk not to display field $13?

Example:
1/2/3/4/5/6/7/8/9/10/11/12/13/14/15/16/17/18/19/20/...
Result:
1/2/3/4/5/6/7/8/9/10/11/12/14/15/16/17/18/19/20/...

The content of the field in question is not known.
Cheers

September 14th, 2006, 05:26 AM

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Join Date: Jul 2006

Location: Dublin, Ireland

Posts: 174

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Try this:

Code:

awk -F/ '{
        for (i = 1; i < NF; i++) {
                if (i != 13) {
                        printf "%s/", $i;
                }
        }

        printf "\n";
}' /path/to/file

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