Bourne Shell scripting help

I am trying list all the comments (with line numbers) in a given file.

For simplicity, all coments start with // and there is a space before and after the slashes. My problem is not listing the comments with the line numbers, it is that I do not want to list the entire line, just whatever is after the // token. For example if I have:

x = 0; // x is equal to zero

if use grep -n " //" $2 , then it lists the whole line:

1: x = 0; // x is equal to zero

Instead I would like it to list everything after the comment like this:

1: x is equal to zero

I am assuming that you can use regualr expressions but that is honestly something I am having trouble grasping. If anyone can help me, I would be very grateful.

Thank you in advance.

-Sweetness

I realize now that I will need to use awk but have no clue where to get started. I am trying to understand what is out there on the web, but am still confused as to how I can solve my problem with awk.

-Sweetness

no need of awk for that.
to numbering all lines in filename use
grep -n . filename
or
nl -ba filename (see man pages)
then pipe the output to sed, eg
grep -n . filename¦sed -n 's/^\([0-9]*[0-9]:\)\(.*\/\)\(.*\)/\1 \3/p'
awk is a fantastic tool, not appropriated in this case
you also could convice 'sed' to count lines, this is an other chaper.

In awk it is quite straitforward:

awk '
{
if (match($0, "//"))
printf "%5d. %s\n", NR, substr($0, RSTART)
}
'

Try it.

Regards zlutovsky

yes zlutovsky



awk '/\/\//{ print what-you-want; }'

and stupid for this job, you should learn how awk works.

Thanx for all the help guys.

Out of ignorance why would awk be stupid for this job?

I got it to work with the awk using:

awk 'match($0, "//") { printf("line %d : %s\n", FNR, substr($0, RSTART+2)); }' $file


Again, thankl you all for the help.

-Sweetness

But dear guggach, have you tried my solution? I assure you, I know awk quite well and before publishing my suggestions, I test them on the computer. Do it too, probatum est.

Regards zlutovsky