Can't work out a pattern that will match a certain string!

I'm trying to do a case statement, where one of the patterns must identify any parameters which don't have a '.' (dot in them),
i.e., if my list of variable were

red.txt blue.txt yellow.txt green

I would need the pattern to identify the 'green' one, as this doesn't have a . in it.
I've been trying patterns along the line of this:

*'.'*)

but this identifies every variable name, with or without a dot in it. Been trying to do this for days now!!
Thanks very much for any help.
Jess

Hello,

perhaps I do not understand properly what you mean. On HP-UX under Bourne shell the simple pattern *.* does the yob:

:
while read P ; do
case $P in
*.*) echo "here is a dot:" $P;;
*) echo "without a dot:" $P;;
esac
done <<!
red.txt
blue.txt
yellow.txt
green
!

Try it

[QUOTE=zlutovsky]

case $P in
*.*) echo "here is a dot:" $P;;
*) echo "without a dot:" $P;;
esac
QUOTE]

That was what I needed! I needed put this in a case statement of its own so I could use the 'anything else' option!
Thanks v much! Your help is much appreciated!