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#1
June 6th, 2007, 03:23 AM
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Checking user login
hi, this one those very helpful sites that i have been to.
 So im trying to write a bash script which checks if any user has logged-in from more than one terminals, if yes, then display the no. of those logins. So this is how far i have managed to reach, Code:
echo -n "Enter Username : ";
read user;
echo -n "Enter terminal no. : ";
read term;
last $user | awk '{ print $2 }' | grep -c "^pts.$term" >temp
val=`<temp`;
awk '{
if ($val > 1)
printf $user," has logged in terminal pts/",$term," ",$val," times";
}'
i get "unexpected file end" error. Please help. 
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#2
June 6th, 2007, 08:50 AM
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There's a couple of problems with your awk command there. awk operates on stdin. i.e. you should either pipe the result of a command to awk/read the input from a file.
The second problem is that you're trying to use a bash variable in your awk script. This can be done but not the way you're trying to do it. In any case, bash should be sufficient for your if/else needs Code:
1 echo -n "Enter Username : ";
2 read user;
3 echo -n "Enter terminal no. : ";
4 read term;
5
6 val=$(last $user | awk '{ print $2 }' | grep -c "^pts/$term")
7
8 if [ $val -gt 1 ]; then
9 echo ${user} has logged in terminal pts/${term} ${val} times
10 fi
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#3
June 6th, 2007, 12:11 PM
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Thanx
im trying hard to improve my skills.you have been a great help. 
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