cut the fields from last

Can any one let me know how to cut the fields from last.

For example, If I have the data in the file named "data" and the column delimiter is "-".

content of data file :
===============
1-abcd-testthis-10
2-sdsd-secndlin-11
3-ffgf-thirdlin-12
4-jiku-fourthli-13

cut -d '-' -f 1
Then I get the first column. (1,2,3,4)

But now I want to get the first column from the end. (10,11,12,13)

Thansk for your time.

No problem:
:
while read LINE; do
echo "$LINE" | awk -F'-' '{print $NF}'
done <<!
1-abcd-testthis-10
2-sdsd-secndlin-11
3-ffgf-thirdlin-12
4-jiku-fourthli-13
!

Try it.

a) read man pages
b) did you try: cut -d '-' -f 4
c) forget awk && perl for such kind of jobs, cut and sed are your (ONE liner) friends

sed -e 's/.*-\(.*\)$/\1/' file

My requirement is to get the first column from the end not the "4th" column. For simplicity, I had taken a row with 4 columns. In fact I am interested to cut the fields from the end.

Thanks.

What zlutovsky suggested works for me:

UUOC

awk -F- '{print $NF}' file

Yes, 'useless use of cat' indeed. My bad; thanks for pointing that out.