Getting line surrounding your grep keyword

I am looking to create a script where I can do a search on a keyword and not only get the lines it shows up on but 3 lines above and below its. I am using HP-Unix. Grep on my machine does not have -A or -B. It may have sever occurance of the same search. I also plan to it to a temp file that I can read out of.

Thanks,

I have had to do something similar - what I did was to use the -n option (I think it was) of grep to return the line number, then use that (suitably added/subtracted from) with sed. I only had a small file so that was ok for me. If you have a big file you may wish to use another method.
awk may be of use - keep a rolling track of current line - 3, -2, and -1 and when you find your keyword print them, and following 3 lines out.

A barbarian way of doing this could be to write each line of your input into a work file, and grep -q on each one read this way. If the grep is successful, you can print the tail -3 of the workfile.

Not as quick as an awk call I´m afraid. Well, I said it was barbarian.

Not sure I understood what you wanted but


on this data:
finds the line bad at line 4 and displays line 3,4,5

Thinking about, changed my mind. Easy to change small things
Using the example file above:

seems to be what you're asking for...