grep for group of lines

Unix guru,

How do I grep a file for "REB" so the output shows the 3 lines above and below each "REB" line (including "REB" line)? I used to have a simple grep/sed/awk to do it but I lost it. I thought it used grep and tail, but so far my attempts don't work.

Thanks,
Ron

not that I consider myself a guru, but this is easy enough to clear up ...

read the manpage for grep. Those are the first few options listed:

-Steven
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Steve,

I checked man page for /usr/bin/grep and /usr/xpg4/bin/grep on SunOS5.8. They don't support -B and -A???

Thanks,
Ron

yes ron A|B are on solaris not supported, maybe is this a gnu grep.
not very easy.
if you always have exactly 3lines below and 3lines after, split -7 can be
an approach, else read in awk|perl|c the whole file in an array ...

ouch! ..ok. I don't have solaris running anywhere anymore.

-Steven