Help converting Bash to Korn

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April 6th, 2006, 02:42 AM

GlobeTrotter

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Join Date: Jan 2005

Posts: 70

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Help converting Bash to Korn

ok for the past while i have been developing a script using Cygwin which uses the Bash(bourne again shell).. i thought all was going well until i then uploaded it to the unix OS i have to use in work, which is the korn shell. now it's throwing up all sorts of errors

time is pressing and iv had many trial and error sessions.. changing brackets etc

my code is this:

Code:

#!/bin/bash

while [ 1 ]
do
	printf "\n begin \n\n"

	dir=*	
	for i in $dir		
	do
	   if [ -f "$i" ]
	   then
		  arr=( "${arr[@]}" "$i" )
	   fi
	done

	test=""
	file=""
	i=0
	while [ $i -lt "${#arr[@]}" ];
	do
	    file=${arr[$i]}
	    test=`expr match "$file" '\(^bdy\)'`
	    if  [ -n "$test" ]; 
		then
			printf "$file \t $test \t found match \n"
		elif [ -z "$test" ];
		then  
			printf "$file \t $test \n"
		fi
		test=""
		let i=i+1
	done
	printf "\n finished \n"
	sleep 3
	arr=()
	clear
done

basically, it runs in an infinite loop, scanning a particular directory, prints them out and anytime a particular file is found which begins with the letters 'bdy' it will also print 'found match'. it works perfectly in cygwin with the bash shell, now i need the odd syntax change so that the korn shell can deal with it..

can anyone please help or advise me ?
thanks in advance folks,

ciaran

April 6th, 2006, 08:56 AM

stanleypane

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Join Date: Oct 2003

Location: Baltimore, MD

Posts: 208

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Arrays are accessed differently in ksh than in bash. i.e.

Code:

To display all values:

    echo ${arr[*]}

To display number of values:

    echo ${#arr[*]}

To add to an array:

    set -A arr VALUE1 VALUE2 VALUE3 ...

The arrays are probably whats causing you the most trouble when you move this script to ksh.

April 6th, 2006, 02:51 PM

GlobeTrotter

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Join Date: Jan 2005

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Quote:

Originally Posted by stanleypane

Arrays are accessed differently in ksh than in bash. i.e.

Code:

To display all values:

    echo ${arr[*]}

To display number of values:

    echo ${#arr[*]}

To add to an array:

    set -A arr VALUE1 VALUE2 VALUE3 ...

The arrays are probably whats causing you the most trouble when you move this script to ksh.

cheers stanley thanks for that.

2 more things

i tried

for i in *
do
set -A arr $i
done

but this didn't add the files in the dir to the array

and secondly i know about regegular expressions, having did them before in java and perl. the question is to do with grouping. /.*(bdy)/

with perl and java $1 would be equal to bdy but it's not working with shell scripting. was just wondering if it was possible and whats the syntax like. cheers again dude
peace out
ciaran

April 6th, 2006, 04:30 PM

stanleypane

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Join Date: Oct 2003

Location: Baltimore, MD

Posts: 208

Time spent in forums: 4 Days 7 h 4 m 19 sec
Reputation Power: 21

You're overwriting your array with a single value during each iteration. Try setting the array like so:

Code:

j=0

for i in *
do
  arr[$j]=$i
  j=`expr $j + 1`
done

As for recalling a matched regex, I'm not sure it's possible with expr. I'm not quite sure I understand why you need to do this. You know the matched string will always be "bdy" so you can just manually insert "bdy" where it needs to go, correct?

FYI: ksh has rudementary regex matching built in for file names. Your "test=blah blah" routine could be shortened by using the following if statement:

Code:

if [ $file = ?(bdy*) ]
then
  # matched code goes here
fi

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