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#1
August 23rd, 2004, 09:36 PM
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I was forced to quit :(
halo,
I have a C-shell script below to let user input an integer. It's ok but if you enter a string like "abd", the program will quit with a mesage @: Expression syntax. How can I check that a user enters a string ? Or can I control my script not to quit even a user enters anything other than integer ? #!/usr/bin/csh -f echo -n "Please input an interger and it will be shown in minute --> " @ yourNum = $< set myVar = $yourNum echo $myVar | egrep -s '^[-+]?([0-9]+\.[0-9]+|[0-9]+\.|\.[0-9]+|[0-9]+)([eE][-+] ?[0-9]+)?$' if (! $status) then echo "input is numeric" endif @ num = $myVar if ( $num < 0 ) then echo "Number cannot be less than zero" else @ showInMin = $num / 60 @ showInSec = $num % 60 echo "This is min " $showInMin echo "This is sec " $showInSec endif
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#2
August 24th, 2004, 01:33 AM
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don't write csh-scripts, it's buggy.
use sh , it's easy, stable and sure runs on all *nix. ksh and bash are also alternatives. Code:
while .
do
read num
case ${num:=q} in q) break
;; [0-9]*[0-9])
;; *) echo error; continue
;; esac
# shell is not the tool 4 arithm. computing...
set `echo "$num % 60; $num / 60" | bc`
echo sec=$1 min=$2
done
Last edited by guggach : August 24th, 2004 at 01:34 AM. Reason: typo
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