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#1
August 11th, 2006, 10:36 AM
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Korn shell script giving error
I am sorry, this is really trivial, yet I am not able to understand what the problem is!
I am using korn shell and running this script Code:
#!/bin/ksh keep=3 while [ $keep -eq 1 ]; do echo $keep keep=$(($keep-1)) done I am getting this error: `keep=$' unexpected I am not able to understand it because keep=$(($keep-1)) works fine on prompt. Please help regarding this. Thanks Asty
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#2
August 11th, 2006, 10:58 AM
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Quote:
The problem is that it's not entering the loop, as a result of the condition you're specified (while $keep -eq 1), keep is initially 3 so it will not enter the loop. Perhaps you meant while $keep -ne 0 ?
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#3
August 11th, 2006, 11:13 AM
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try:
Code:
#!/bin/ksh
keep=3
while [[ $keep -gt 0 ]]; do
echo $keep
keep=$(($keep-1))
done
Use [[ ]] for tests in ksh. It allows more flexibility. There are other test numeric operators: -gt greater than -lt less than -eq equal -ne not equal
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