KSH help! passing variables to functions

okay, I have the following code. (korn shell script in unix).

function abc
{
print $1
}

#main starts here

for((i=1; i<$#; i++))
do
abc $i
done
#end of program

#the $# variable is a count of the number of vars #passed to main from the command line.

#here, $i is the first command line variable. I want to #pass that variable to function abc. then i want the
#value of $2, then value of $3, etc.

when i do this, it actually passes $i rather than the value of $i. i have tried every type of syntax modification to the function call, but can't seem to make this work. any help would be GREATLY appreciated. thank you!

I don't think you understand how variables work. If you do:

i="hello"
echo $i

The echo statement is print "hello". If you put a statement like
hello="good-bye"
in front of it, that won't change anything

I understand that. im just not sure how i would pass the value of $1 for example (first iteration of loop), to function abc.... i realize that abc $i will not work, and i understand why, but i don't know what to use in its place.

I would do something like this:

function abc
{
print $1
}

#main starts here

while(($#))
do
abc $1
shift
done

You have instructed the system to display numbers 1, 2, 3, etc and it has done so.

Write

eval abc \$$i

instead of

abc $i

Regards zlutovsky