need help with simple shell program

i am have a problem with my program i don't know how to correct my errors. here's the program
and errors:

#include <stdio.h>
#include <iostream.h>
#include <sys/types.h>
#include <sys/wait.h>

void parse(char *line, char **argv)
{
argv[0] = (char *)malloc (100);
argv[1] = (char *)malloc (100);
argv[2] = NULL;
int counter = 0;
while(*line != '\0')
{
char *temp_val = argv[counter];
while((*line != '')&&(*line != '\t')&&(*line != '\n')&&(*line != '\0'))
{
*(temp_val++) = *(line++);
}
*temp_val = '\0';
counter ++;
while((*line == '' || *line == '\t' || *line == '\n')&&(*line != '\0'))
{
line++;
}
}
}

int main()
{
char line[100];
char *argv[100];
while(1)
{
cin.getline(line,100);
parse(line, argv);
if strcmp(argv[0], "exit")==0) exit (0);
{ int childpid;
childpid = fork();
if(childpid > 0)
{
waitpid(childpid,0,0);
}
if (childpid ==0)
{
execvp(argv[0],argv);
}
}
return 0;
}

parse error before '(' token that does this mean?

that 'simple shell program' will mostly called a 'c-program'
(i can|will not read it)