Previous Date In LInux

Hi Guys

I am working on Solaris 9.0. How can I subtract system date by 1,2,3 days and stored into an variable

Help Me pls


Regards

Amit Midha (Oracle DBA)

Here is a pointer to an article on the subject:

http://www.samag.com/documents/s=8284/sam0307b/0307b.htm

I had the same problem and I have solved it by simple C program delta_days:

You can call it this way: delta_days -1 %D
Format specification: see man page man strftime

/************************************************************************/
/* Program to generate datum that differs from current time */
/* of a given number of days */
/* Call: delta_d number_of_days format */
/* format - see man strftime */
/* delta_d < 0 : shift into the past */
/* delta_d = 0 : current time and datum */
/* delta_d > 0 : shift into the future */
/************************************************************************/
#include <stdio.h>
#include <sys/types.h>
#include <time.h>

#define BUFL 1000

int main (int argc, char *argv[])
{
time_t t; /* Time in seconds of era */
unsigned long d; /* total number of days */
char * endc; /* ending character of argv[1] */
struct tm * loct; /* the time structure */
char buf[BUFL]; /* working space */

if (argc != 3) {
fprintf (stderr, "%s: call: %s count_of_days format\n", argv[0], argv[0]);
exit (1);
}

d = strtol (argv[1], &endc, (int)10);
if (*endc != 0) {
fprintf (stderr, "%s: count_of_days must be an integer\n", argv[0]);
exit (1);
}

t = time (NULL) + d*24*60*60;
loct = localtime (&t);
strftime (buf, (size_t) BUFL, argv[2], loct);
printf ("%s\n", buf);
}

Regards