reading from files

I am using the current script to cut out required fields from a flat file with several lines.

#/bin/sh
#/bin/sed

grep denied /tmp/filename > deniedres
cat -ve newfile > newfile1

linecount=`grep -c denied newfile1`
linecount=`expr $linecount + 1`
lc=1
until [ $lc = $linecount ]
do
echo $linecount
echo $lc
tempres=`grep denied newfile1|cut -d '$' -f $lc`
echo "Tempres : $tempres"
temp=1
event="event: "
while [ $temp -lt 17 ]
do
line=`echo $tempres | cut -f $temp -d ';'`
#echo " $line"
if [ $temp = 1 ] || [ $temp = 3 ] || [ $temp = 16 ]
then
event=`echo $event $line`
fi
temp=`expr $temp + 1`
done
lc=`expr $lc + 1`
done

echo $event

The script is supposed to go line by line and extrace and display the required fields by cutting them (fields 1,3 and 16)
but what happens is that the grep denied newfile1|cut -d '$' -f $lc greps the first field of ALL the lines instead of looping line by line. is there anyway i can read from the file line by line and then extract out the fields, then proceed on to the next line? Thx in adv.

Try this code to read a file line by line:



Using a while loop can take a long time to run and if you are parsing through larger input files you might want to try using sed or awk.