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#1
October 26th, 2009, 10:27 PM
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Sed question
I am having a difficult time trying to figure out this case in a bash shell.
What I want to do is display all the lines that appear between parentheses in a text file. Example TextFile: My name is NookLogan (Nook for short) I would like to further my knowledge in UNIX (I am having trouble with this one little case and I can't seem to figure it out) The output I would like is: (Nook for short) (I am having trouble with this one little case and I can't seem to figure it out) I've tried sed -n '/(/,/)/p' TextFile This returns all the lines starting from (Nook for short) to the end. Any help would be much appreciated NookLogan
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#3
October 29th, 2009, 04:34 PM
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I don't know that sed will be able to do this for you.. I would suggest perl or awk.
The closest I could iron out quickly w/ sed was this: Code:
sed -n '/[()]/p' But that does not traverse lines
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#4
November 17th, 2009, 04:56 AM
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Quote:
sed -n '/(/,/)/p' filename works for me
__________________
working on Solaris[5-9], preferred languages french and C.
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