shell script to remove a particular line across multiple files in a directory ???

Hi,

I have a problem! I want to finad all java files in a directory structure (its a really big directory structure!), and go into the java code and remove the first line in the code if it is something (specifically, %modified....). How do I do this?

I was thinking of using shell scripts? SED?

Please help!!!!

Yes you can use the find utility in conjunction with sed.

Here is an example which you will need to modify for
your particular purposes



or you could use a loop



Of course with sed you need to save the output to
a temporary file and replace the original file with
the temporary file.

if it's a oneliner you're after, I rekkon this'll do the job (when run from the top directory (ie root of source tree):

find . -type f -name "*java" | xargs perl -pi -e 's/%modified+//g';

christo

Hi,

Thanks a lot for the help. But when I executed the command it just removed the word from the line. But I want to remove te whole line in which %modified appears.

Thanks

sounds like you just need to meddle with the expression - (ie the bit inside the first / and the second /. You could try just matching everything with *

find . -type f -name "*java" | xargs perl -pi -e 's/%modified*//g';

totally untested of course

christo